How is energy passed in a parallel circuit ?
1 answer:
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Answer:
-36.71%
Explanation:
Using the Generalized Work Energy Principle, the puck is brought to rest by an external force and the system has no kinetic energy
#Denote the stopping distance and force required with a prime and observe from (i) that:
#If stopping distance increases by a factor of 79/50;
So F decreases by 36.71% . we expect force to reduce since the same amount of work is repeatedly done on the system over a long distance.
We have that the gravitational energy is given by: U=mgh where m is the mass of the object (in kg), g is the gravitational acceleration and h is the height of the object (in meters). Hence, h=U/(m*g) where g=9.8 m/s^2. Thus, h=20 m if we substitute.
Similarly, substituting in b, we have that the height of the model plane is 10 m. The kinetic energy is given by: K=
where u is the speed of the object. Hence, solving for u we have u=
. Substituting, we have that u=5m/s.
Similarly, substituting in b, we have that the height of the model plane is 10 m. The kinetic energy is given by: K=