The expression for the block's centripetal acceleration is derived as ω²r or v²/r.
<h3>
What is centripetal acceleration?</h3>
The centripetal acceleration of an object is the inward or radial acceleration of an object moving in a circular path.
The expression for the block's centripetal acceleration is derived as follows;
ω = dθ/dt
where;
- ω is the angular speed
- θ is the angular displacement
- t is the time of motion
ac = ω²r
where;
- r is the radius of the circular path
Also, ω = v/r
ac = (v/r)²r
ac = v²/r
Thus, the expression for the block's centripetal acceleration is derived as ω²r or v²/r.
Learn more about centripetal acceleration here: brainly.com/question/79801
Answer:
a) t = 3.2 s
b) 
Explanation:
a) El tiempo requerido para llegar al suelo se puede calcular usando la siguiente fórmula:

En donde:
: es la altura inicial = 50 m
g: es la gravedad = 10 m/s²

Entonces, el tiempo requerido para llegar al suelo es 3.2 s.
b) La rapidez de la pelota justo antes del choque es el siguiente:

En donde:
: es la velocidad inicial = 0 (dado que se deja caer en resposo)

Por lo tanto, la rapidez de la pelota justo en el momento anterior del choque es -32 m/s (el signo negativo es porque la pelota está cayendo).
Espero que te sea de utilidad!
Answer:
Normal force of 10,000N
Explanation:
From the question, the weight the car exerts on the pavement is 10,000N.
The pavement exerts upward and perpendicular contact force called normal force on the car to support its weight. Also, the normal force is equal and opposite to the weigh of the car.
Hence the pavement exerts normal force of 10,000N back on the car to prevent it from passing through it.
Answer:
The other angle is 75⁰
Explanation:
Given;
velocity of the projectile, v = 10 m/s
range of the projectile, R = 5.1 m
angle of projection, 15⁰
The range of a projectile is given as;

To find another angle of projection to give the same range;

<u>Check: </u>
sin(2θ) = sin(2 x 75) = sin(150) = 0.5
sin(2θ) = sin(2 x 15) = sin(30) = 0.5