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ch4aika [34]
3 years ago
8

A store is having a sale on almonds and jelly beans. For 3 pounds of almonds and 5 pounds of jelly beans, the total cost is $19

. For 9 pounds of almonds and 7 pounds of jelly beans, the total cost is $35 . Find the cost for each pound of almonds and each pound of jelly beans.
Cost for each pound of almonds: $
Cost for each pound of jelly beans:$
Mathematics
1 answer:
yaroslaw [1]3 years ago
6 0

Answer:

Almond: $7/4 per pound

Jelly Bean: $ 11/4 per pound

Step-by-step explanation:

A: almond

J: jelly bean

3A + 5J = 19 .... multiply 9 each side

27A + 45J = 171 .....(1)

9A + 7J = 35 .....multiply 3 each side

27A + 21J = 105 ....(2)

(1) - (2)    24J = 66

J = 66/24 = 11/4

3A + 5 x 11/4 = 19

3A = 21 / 4

A = 7/4

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Answer:

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3 years ago
If a square is dilated by a factor of 2 what is the measure of each individual angle
vodomira [7]

Answer:

4:1

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3 years ago
Miguel saved $355 in 5 weeks. He saved equal amounts of money each week. How much money would he save in 15.5 weeks ?
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Answer:

A

Step-by-step explanation:

$355:5

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5 divided by 5=1

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3 years ago
An engineer designed a valve that will regulate water pressure on an automobile engine. The engineer designed the valve such tha
natita [175]

Answer:

Step-by-step explanation:

Given that:

Population Mean = 7.1

sample size = 24

Sample mean = 7.3

Standard deviation = 1.0

Level of significance = 0.025

The null hypothesis:

H_o: \mu = 7.1

The alternative hypothesis:

H_a: \mu > 7.1

This test is right-tailed.

degree \ of \  freedom=  n - 1 \\ \\ degree \  of \  freedom  =  24 - 1 \\ \\ degree \ of \  freedom   = 23

Rejection region: at ∝ = 0.025 and df of 23, the critical value of the right-tailed test t_c = 2.069

The test statistics can be computed as:

t = \dfrac{ \hat X - \mu_o}{\dfrac{s}{\sqrt{n}}}

t = \dfrac{ 7.3-7.1}{\dfrac{1}{\sqrt{24}}}

t = \dfrac{0.2}{0.204}

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Decision rule:

Since the calculated value of t is lesser than, i.e t = 0.980 < t_c = 2.069, then we do not reject the null hypothesis.

Conclusion:

We conclude that there is insufficient evidence to claim that the population mean is greater than 7.1 at 0.025 level of significance.

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3 years ago
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Answer:

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