We are given : Zeros x=7 and x=4 and leading coefficent 1.
In order to find the quadratic function in standard form, we need to find the factors of quadratic function first and the multiply by given leading coefficent.
For the given zeros x=7 and x=4, we get the factors (x-7) and (x-4).
So, we need to multiply (x-7) and (x-4) by foil method.
We get
(x-7)(x-4) = x*x + x* -4 -7*x -7*-4
x^2 -4x -7x +28.
Combining like terms, we get
-4x-7x = -11x
x^2 -4x -7x +28 = x^2 -11x +28.
Now, we need to multiply x^2 -11x +28 quadratic by leading coefficent 1.
We get
1(x^2 -11x +28) = x^2 -11x +28.
Therefore, the required quadratic function in standard form is x^2 -11x +28.
Answer: y = 0.5, x = 50
Step-by-step explanation: Both triangles in the picture are isosceles, telling us that the 2 angles at the bottom are congruent. With this, we can find y by doing the following:
a triangle has 180 degrees so we subtract the given 50 which gives us 130
2(2y + 64) = 130
4y + 128 = 130
y = .5
This means that the bottom 2 angles are both 65. Since the top angle of the second triangle is supplementary to the bottom angle of the first one, the top angle of the second triangle is 115. So, we find x by:
2(45 - x/4) = 65
x = 50
This means the bottom 2 angles of the second triangle are both 32.5.
This work is faster rate than grading 36 assignments in 30 minutes because :
25 ÷ 20 = 1.25
1.25 hw assignment per minute
36 ÷ 30 = 1.2
1.2 hw assignments per minute
