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Paladinen [302]
3 years ago
8

5

Mathematics
1 answer:
Natalija [7]3 years ago
5 0

Answer:

Step-by-step explanation:

Two perpendicular line means one's slope is negative inverse to the another one.

Therefore, the slope of y = -3x + 2 is -3.

Assume its perpendicular line is 3y = x +k, this line pass through (-2,8)

24 = (-2) + k => k = 26

3y = x+26

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Nady [450]
3:2, easy. 

the rest you dont need to read i just need 20 characters to "explain it well".
4 0
3 years ago
3/5 of a Conductors Club went on the last camping trip.If 39 people went on the trip, how many are in the club?
Lerok [7]
The answer is 65 people in the club.
4 0
3 years ago
Urgent, please i will give brainliest
Ne4ueva [31]

Answer:

1. \frac{\sqrt{13} }{3}

2. 3.2362

3. \frac{60}{11}

Step-by-step explanation:

1.

Cot is the trigonometric ratio defined by "adjacent" over "opposite". <em>So, adjacent = 2 and opposite = 3.</em>

By pythagorean theorem, we have the "hypotenuse" as  \sqrt{2^2+3^2}=\sqrt{13}

Csc is defined as the trig ratio "hypotenuse" over "opposite". <em>We know the sides, so Csc \theta = \frac{\sqrt{13} }{3}</em>

<em />

<em>First answer choice is right.</em>

<em />

2.

By definition, Csc \theta is the inverse of Sine \theta. <em>If given the value of sin theta, to find value of csc theta, we take the reciprocal of it. Hence:</em>

Csc\theta=\frac{1}{0.3090}\\=3.2362

Third answer choice is right.

3.

By definition tan and cot are inverse of each other. <em>So the value of tan is the reciprocal of the value of cot.</em> We can simply "flip" the value of tan theta to get the value of cot theta. Hence:

Cot\theta=\frac{60}{11}

Third answer is right.

3 0
3 years ago
Read 2 more answers
How many terms are there in the sequence 1, 8, 28, 56, ..., 1 ?
BabaBlast [244]

Answer:

9 terms

Step-by-step explanation:

Given:  

1, 8, 28, 56, ..., 1

Required

Determine the number of sequence

To determine the number of sequence, we need to understand how the sequence are generated

The sequence are generated using

\left[\begin{array}{c}n&&r\end{array}\right] = \frac{n!}{(n-r)!r!}

Where n = 8 and r = 0,1....8

When r = 0

\left[\begin{array}{c}8&&0\end{array}\right] = \frac{8!}{(8-0)!0!} = \frac{8!}{8!0!} = 1

When r = 1

\left[\begin{array}{c}8&&1\end{array}\right] = \frac{8!}{(8-1)!1!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 2

\left[\begin{array}{c}8&&2\end{array}\right] = \frac{8!}{(8-2)!2!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} =2 8

When r = 3

\left[\begin{array}{c}8&&3\end{array}\right] = \frac{8!}{(8-3)!3!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 4

\left[\begin{array}{c}8&&4\end{array}\right] = \frac{8!}{(8-4)!4!} = \frac{8!}{4!3!} = \frac{8 * 7 * 6 * 5 * 4!}{4! *4*3* 2 *1} = \frac{8 * 7 * 6*5}{4*3 *2 *1} = 70

When r = 5

\left[\begin{array}{c}8&&5\end{array}\right] = \frac{8!}{(8-5)!5!} = \frac{8!}{5!3!} = \frac{8 * 7 * 6 * 5!}{5! *3* 2 *1} = \frac{8 * 7 * 6}{3 *2 *1} = 56

When r = 6

\left[\begin{array}{c}8&&6\end{array}\right] = \frac{8!}{(8-6)!6!} = \frac{8!}{6!2!} = \frac{8 * 7 * 6!}{6! * 2 *1} = \frac{8 * 7}{2 *1} = 28

When r = 7

\left[\begin{array}{c}8&&7\end{array}\right] = \frac{8!}{(8-7)!7!} = \frac{8!}{7!1!} = \frac{8 * 7!}{7! * 1} = \frac{8}{1} = 8

When r = 8

\left[\begin{array}{c}8&&8\end{array}\right] = \frac{8!}{(8-8)!8!} = \frac{8!}{8!0!} = 1

The full sequence is: 1,8,28,56,70,56,28,8,1

And the number of terms is 9

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3 years ago
Find The value of X to the nearest tenth<br> A 7.0<br> B 4.7<br> C 5.7<br> D 8.2
vredina [299]
Here is the correct answer, and explanation for how to get the answer, and a way to remember how to use them for next time :)

3 0
3 years ago
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