Explanation:
The given data is as follows.
50 ml of 
, 50 ml of 
And, it is known that at STP 1 mole of a gas occupies 22.4 L. Hence, moles present in 50 ml of gas are as follows.
(As 1 L = 1000 ml)
= 
moles
So, according to the given equation moles of reacts with moles of .
Hence, moles of 
is equal to the moles of and .
Therefore, moles of = moles
1 mole of = 22.4 L
moles = 
= 50 ml of product
Thus, we can conclude that 50 ml of products if pressure and temperature are kept constant.
The balanced equation for the above reaction is
2Al + 6H₂O ---> 2Al(OH)₃ + 3H₂
stoichiometry of Al to H₂ is 2:3
number of Al moles reacted - 78.33 g / 27 g/mol = 2.901 mol
according to molar ratio
2 mol of Al forms - 3 mol of H₂
therefore 2.901 mol of Al - forms 3/2 x 2.901 = 4.352 mol
molar volume states that 1 mol of any gas occupies a volume of 22.4 L at STP
if 1 mol occupies 22.4 L
then 4.352 mol occupies - 22.4 L/mol x 4.352 mol = 97.48 L
volume occupied by H₂ is 97.48 L
Answer:
It has 2 eyes
Explanation:
Quantitive observation means that it is facts based of numbers, therefore you can count how many eyes it has, but not that it has red eyes
Answer:
C = 0.2349 J/ (g °C)
Explanation:
Mass, m = 894.0g
Initial Temperature = −5.8°C
Final Temperature = 17.5°C
Temperature change = 17.5°C - (−5.8°C) = 23.3
Heat, H = 4.90kJ = 4900 J
Specific heat capacit, C = ?
The relationship between these quantities is given by the equation;
H = mCΔT
C = H / mΔT
C = 4900 / (894)(23.3)
C = 0.2349 J/ (g °C)
