The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
We have given that,
A line that has a gradient of 2 and passes through the line (1, 4).
We have to determine the equation of the line,
<h3>What is the gradient?</h3>
The gradient also known as the slope is the defined as
Gradient (m) = change in y coordinate / change in x coordinate
The equation of a line passing through a given point is given by the following equation
y – y₁ = m(x – x₁)
How to determine the equation of the line passing through point (1,4)
x coordinate (x₁) = 1
y coordinate (y₁) = 4
Gradient (m) = 2
Equation =
y – y₁ = m(x – x₁)
y – 4 = 2(x – 1)
Clear bracket
y – 4 = 2x – 2
Make y the subject by adding 4 to both sides
y – 4 + 4 = 2x – 2 + 4
y = 2x + 2
The equation of the line which has a gradient of 2 and passes through the point (1,4) is y = 2x + 2.
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1) At 95% Confidence interval the critical value is z0.025= 1.96 Margin of error = 0.02 Or, z0.025* sqrt(p(1 - p)/n) = 0.02 Or, 1.96 * sqr
V=B+15
V+2B=180
Therefore:
3B+15=180
B=55
V=70
Check:
V+2B=180
70+2(55)=180
70+110=180
180=180. Checks.
Your answer would be 3160.
the adjacent angles in a parallelogram
