9/2 + 5/2
11/2
1/5
Answer: 70/11 (<span>6.363636)</span>
Answer:
Step-by-step explanation:
From the given information:
r = 10 cos( θ)
r = 5
We are to find the the area of the region that lies inside the first curve and outside the second curve.
The first thing we need to do is to determine the intersection of the points in these two curves.
To do that :
let equate the two parameters together
So;
10 cos( θ) = 5
cos( θ) = 

Now, the area of the region that lies inside the first curve and outside the second curve can be determined by finding the integral . i.e









The diagrammatic expression showing the area of the region that lies inside the first curve and outside the second curve can be seen in the attached file below.
Answer:
B would equal -4
Step-by-step explanation:
Answer:
His friend gave Greg a 20$ bill.
Step-by-step explanation:
35.23+10.75+17.25=63.23
63.23-50= 13.23
13.23+6.77= 20
9514 1404 393
Answer:
x^3 -4x^2 +12x -27
Step-by-step explanation:
Use the distributive property.
= (x^2 -x +9)(x) +(x^2 -x +9)(-3)
= x^3 -x^2 +9x -3x^2 +3x -27
= x^3 -4x^2 +12x -27 . . . . . collect terms