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GuDViN [60]
3 years ago
14

A bicycle wheel of radius 14 cm is mounted at the middle of an axle 96 cm long. The tire and rim weigh 23 N. The wheel is spun a

t 12 rev/s, and the axle is then placed in a horizonal position with one end resting on a pivot
a. What is the magnitude of the angular momentum due to the spinning of the wheel? (Treat the wheel as a hoop.)
b. What is the angular speed of precession? rad/s How long does it take for the axle to swing through 360 degree around the pivot?
c. What is the magnitude of the angular momentum associated with the motion of the center of mass, that is, due to the d. precession? In what direction is this angular momentum? up up or down, depending on the direction of in part (a) down
Physics
1 answer:
ollegr [7]3 years ago
8 0

Answer:

a. L =3.465 J.s

b. 3.186 rad/s

c. T =  1.972 s

d. Lp = 0.022 J.s; up or down, depending on the direction of L

Explanation:

(a)We have the formula for angular momentum as

L = I*w where I = moment of inertia = M*R^2

L = (23/9.81) * 0.14^2* (24*pi) J.s = 3.465 J.s

(b) ω = M*g*D/L

where D = L/2 = 0.96/2 = 0.48m

ω = (23* 0.48/3.465) rad/s = 3.186 rad/s

(c) T = 2π/ω

T = 2*π/3.186 s = 1.972 s

(d) Lp = M*D^(2*w)

Solving with mass M, D and angular velocity ω

Lp = 0.022 J.s; up or down, depending on the direction of L

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1. Which statement about friction is true?(1 point) A. Static friction and kinetic friction in a system always act in the same d
ArbitrLikvidat [17]

Answer:

true 1Ay 2D

Explanation:

1) In this exercise you are asked to investigate which statements are true

A) True. The friction force opposes the movement caused by the external force,

B) False. Mantuano in the opposite direction force

C) False. The static and scientific friction force act in the same direction, since the second appears when the movement does not start and the static friction decreases.

D) Fale the static and kinetic friction forces act in the same direction

2) How to overcome friction on a ramp

A) False. If the texture of the surface becomes rough, the friction force increases

B) False. Pressing the brick against the surface increases the normal and as the friction is proportional to the normal, it also increases

C) False. By lowering the table the weight component in the friction direction decreases

D) True. When lifting the board, the weight component increases and therefore can become greater than the friction

          Wx-fr = ma

           W sin tea - my mg cos tea = m a

As it increases, the sine increases and the cosine decreases.

3 0
2 years ago
What is the radius of a tightly wound solenoid of circular cross-section that has 180turns if a change in its internal magnetic
Nata [24]

Answer:

Radius of cross section, r = 0.24 m

Explanation:

It is given that,

Number of turns, N = 180

Change in magnetic field, \dfrac{dB}{dt}=3\ T/s

Current, I = 6 A

Resistance of the solenoid, R = 17 ohms

We need to find the radius of the solenoid (r). We know that emf is given by :

E=N\dfrac{d\phi}{dt}

E=N\dfrac{d(BA)}{dt}

Since, E = IR

IR=NA\dfrac{dB}{dt}

A=\dfrac{IR}{N.\dfrac{dB}{dt}}

A=\dfrac{6\ A\times 17\ \Omega}{180\times 3\ T/s}

A=0.188\ m^2

or

A=0.19\ m^2

Area of circular cross section is, A=\pi r^2

r=\sqrt{\dfrac{A}{\pi}}

r=\sqrt{\dfrac{0.19}{\pi}}

r = 0.24 m

So, the  radius of a tightly wound solenoid of circular cross-section is 0.24 meters. Hence, this is the required solution.

5 0
3 years ago
A 2.5g copper penny is given a charge of -4.0*10^-9c. how mny excess electrons are on the penny?
Lyrx [107]

Answer : The excess of electrons on the penny are, 2.5\times 10^{10} electrons

Solution : Given,

Total charge = -4.0\times 10^{-9}C

Charge on electron = -1.6\times 10^{-19}C

Formula used :

\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}

Now put all the given values in this formula, we get the excess of electrons present on the penny.

\text{Excess of electrons}=\frac{\text{Total charge}}{\text{Charge of electron}}=\frac{-4.0\times 10^{-9}C}{-1.6\times 10^{-19}C/e^-}=2.5\times 10^{10}e^-

Therefore, the excess of electrons on the penny are, 2.5\times 10^{10} electrons


7 0
2 years ago
Can anyone answer this for my friend course I am not sure of what I did I don’t take physics but I did it
kogti [31]

Answer:

the total travled is 2.75

Explanation:

because if you divide 110 by 40 you get 2.75

3 0
3 years ago
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