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cricket20 [7]
3 years ago
7

At maximum speed an airplane travels 1720 miles against the wind in 5 hours. Flying with the wind, the plane can travel the same

distance in 4 hours. Let X be the maximum speed of the plane and Y be the speed of the wind. What is the speed of the plane with no wind?
Physics
2 answers:
Basile [38]3 years ago
7 0
An airplane at a maximum speed of 1720 miles against the wind for 5 hours so wha could be the speed of the plane with no wind if the wind could fly the plane with the same distance for 4 hrs and  i think the best answer to this problem is 387 and i hope your satisfied with my answer.
Ede4ka [16]3 years ago
4 0

Answer:

387 miles / hour

Explanation:

X be the maximum speed of plane and Y be the speed of wind.

Speed is the ratio of distance traveled to the time taken by the body.

When the plane travels against the wind, the speed of the plane is X - Y and when the plane is moving with the wind the speed is X + Y.

According to the formula

speed = \frac{distance}{time}

X - Y = \frac{1720}{5}

X - Y = 344 ....(1)

And

X + Y = \frac{1720}{4}

X - Y = 430 ......(2)

Adding both the equations,

2X = 774

X = 387 miles/hour

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3 years ago
Anyone knows this? Please answer... Spam will be reported.
Yakvenalex [24]

Answer:

The correct option is;

The assertion is correct, but reason wrong

Explanation:

The question is with regards to the relationship between work, energy, power, and velocity

The mass of each of the persons running up the staircase = Different

The time it takes each person to run up the stairs = Equal time

Let, 'm₁' and 'm₂' represent the mass of each of the persons that ran up the stairs and m₁ > m₂

Let 't' represent the equal time it takes then to run up the stairs

Let 'h' represent the height of the stairs

The energy, 'E', it takes to run up the stairs is equal to the potential energy, P.E., obtained at the top of the stairs

P.E. = m·g·h

Where;

m = The mass of the person at an elevated height

g = The acceleration due to gravity = Constant

h = The height reached above ground level

Given that the height reached is the same for both of the persons, we have

For m₁, P.E.₁ = m₁·g·h and for m₂, P.E.₂ = m₂·g·h

Therefore, where, m₁ > m₂, we have;

P.E.₁ > P.E.₂

∴ E₁ > E₂

Power, 'P', is the rate at which energy is expended

∴ Power, P = E/t

∴ P₁ = E₁/t  > P₂ = E₂/t

Therefore, the person with the greater mass, 'm₁', uses more power than the person of mass 'm₂', in running up the stairs

Therefore, the assertion is correct

The average velocity, vₐ = (Total distance traveled, d)/(Total time taken, t)

Given that the distance, 'd', covered in running up the stairs by both persons is the same, and the time it takes them to complete the distance, 't', is also the same, we have;

The average velocity of the person with the greater mass m₁ is the same as the average velocity of the person with mass, m₂

Therefore, the reason is wrong

The answer is that the assertion is correct, but reason wrong

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Answer:

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Explanation:

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