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2 years ago

!WILL GIVE BRAINLIEST!

Physics

1 answer:

vazorg [7]2 years ago

8 0

As per angular momentum conservation we can say

$L_i = L_f$

here we know that

$mv_1r_1 = mv_2r_2$

we know that

$v_1 = 1.1 m/s$

$r_1 = 0.6 m$

$v_2 = ?$

$r_2 = 0.15 m$

now from above equation

$2(1.1)(0.6) = 2(v_2)(0.15)$

$v_2 = \frac{(1.1)(0.6)}{0.15}$

$v_2 = 4.4 m/s$

so speed is 4.4 m/s

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Can a body have increasing velocity with decreasing acceleration?

Sergio039 [100]

Sure. The acceleration may be decreasing, but as long as it stays
in the same direction as the velocity, the velocity increases.

I think you meant to ask whether the body can have increasing velocity
with negative acceleration. That answer isn't simple either.

If the body's velocity is in the positive direction, then positive acceleration
means speeding up, and negative acceleration means slowing down.

BUT ... If the body's velocity is in the negative direction, then positive
acceleration means slowing down, and negative acceleration means
speeding up.

I know that's confusing.

-- Take a piece of scratch paper, write a 'plus' sign at one edge and
a 'minus' sign at the other edge. Those are the definitions of which
direction is positive and which direction is negative.

-- Then sketch some cars ... one traveling in the positive direction, and
one driving in the negative direction. Those are the directions of the
velocities.

-- Now, one car at a time:
. . . . . first push on the back of the car, in the direction it's moving;.
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Each push causes the car to accelerate in the direction of the push.

When you see it on paper, all the positive and negative velocities
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3 0

2 years ago

A cat jumps off a piano that is 1.3m high. The initial velocity of the cat is 3m/s at an angle of 37degrees above the horizontal

SpyIntel [72]

Answer:

$x=1.75m$

Explanation:

From the exercise we have that

$y_{o}=1.3m\\v_{o}=3m/s, \beta =37\\$

To find how far from the edge of the piano does the cat strike the floor, we need to calculate its time first

$y=y_{o}+v_{oy}t+\frac{1}{2}gt^{2}$

At the end of the motion y=0m

$0=1.3+3sin(37)t-\frac{1}{2}(9.8)t^{2}$

Solving for t

$t=-0.36 s$ or $t=0.73s$

Since the time can't be negative the answer is t=0.73

Knowing that we can calculate how far does the cat strike the floor

$x=v_{ox}t=3cos(37)(0.73)=1.75m$

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3 years ago

Which of the following elements has the smallest atomic radius?

kondor19780726 [428]

Fluorine it has a atomic radius of 42

7 0

2 years ago

A biologist looking through a microscope sees a bacterium at r⃗ 1=2.2i^+3.7j^−1.2k^μm(1μm=10−6m). After 6.2 s , it's at r⃗ 2=4.6

stiv31 [10]

The Average velocity for the bacterium is 0.75 unit/sec.

Explanation:

The given values are in the vector form

Where,

dS = distance covered

dT = time interval

Now, to calculate distance covered, we have

$|d S|=\sqrt{d S^{2}}$

$d S=r_{2}-r_{1}$

d S=(4.6 i+1.9 k)-(2.2 i+3.7 j - 1.2 k)

d S=(4.6-2.2) i+(0-3.7) j+(1.9+1.2) k

d S=2.4 i-3.7 j+3.1 k

Now, putting these values in the standard formula to evaluate the average velocity, we get;

$v_{a v g}=\frac{|\mathrm{d} S|}{d T}$

$v(a v g)=\frac{|\sqrt{\left\{\left(2.4^{2}\right)+\left(3.7^{2}\right)+\left(3.1^{2}\right)\right\}}|}{7.2}$

As dT=7.2 sec

Now,

Solving the equation, we get;

$v(a v g)=\frac{5.390732789}{7.2}$

$\begin{aligned}&v(a v g)=\frac{5.39}{7.2}\\&v(a v g)=0.748611111\\&v(a v g)=0.75 \text { units / sec }\end{aligned}$

Hence, the average velocity for the bacterium is 0.75 unit/sec.

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3 years ago

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katrin [286]

If the car in the opposite direction turns the signal on your vehicle, then it is only likely to give way and let him or her turn before you make your turn because he or she is in the right of way and by doing this, it will prevent any complication from happening and to be able to show respect and politeness in driving.

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3 years ago