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3 years ago

If a 75 W lightbulb operates at a voltage of 120 V, what is the current in the

Physics

1 answer:

zheka24 [161]3 years ago

4 0

Answer:

Option D. 0.63 A

Explanation:

The following were obtained from the question:

P = 75W

V = 120 V

I =?

But,

P = IV

I = P / V

I = 75 / 120

I = 0.63A

The current in the bulb is 0.63A.

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A(n) __________ is a recording of a motion picture, or television program for playing through a television.

Soloha48 [4]

Answer:

Video

Explanation:

Hope this helps! If it does, drop a 5 star!

4 0

3 years ago

Read 2 more answers

2. What do pitch and loudness have in common?

DanielleElmas [232]

Answer:

Both are subject to a persons interpretation

Explanation:

We hear people describe this when somebody is making an irresistible sound. usually people say the baby has a pitch scream.

5 0

2 years ago

If the atmospheric pressure in a tank is 23 atmospheres at an altitude of 1,000 feet, the air temperature in the tank is 700F, a

liraira [26]

Answer:

W = 289.70 kg

Explanation:

Given data:

Pressure in tank = 23 atm

Altitude 1000 ft

Air temperature in tank T = 700 F

Volume of tank = 800 ft^3 = 22.654 m^3

from ideal gas equation we have

PV =n RT

Therefore number of mole inside the tank is

$\frac{1}{n} = \frac{RT}{PV}$

$= \frac{8.206\times 10^{-5}} 644.261}{23\times 22.654}$

$= 1.02\times 10^{-4}$

$n = 10^4 mole$

we know that 1 mole of air weight is 28.97 g

therefore, tank air weight is $W = 10^4\times 28.91 g = 289700 g$

W = 289.70 kg

6 0

3 years ago

If it takes 32,000 joules of heat to warm 750 g of water, what was the temperature change?(the specific heat of water is 4.18 J/

Firdavs [7]

Answer:

10.21°C

Explanation:

From the question,we are given;

Quantity of heat = 32,000 Joules
Mass of water = 750 g
Specific heat capacity of water = 4.18 J/g°C

We are required to calculate the change in temperature;

We need to know that quantity of heat is calculated by multiplying mass by specific heat then by change in temperature.
That is;

Q = m × c × ΔT

Rearranging the formula;

ΔT = (Q ÷ (m × c))

= 32,000 J ÷ (750× 4.18 J/g°C)

= 10.21°C

Therefore, the change in temperature is 10.21°C

7 0

3 years ago

A 222 kg bumper car moving right at 3.10 m/s collides with a 165 kg bumper car moving 1.88 m/s left Find the total momentum of t

Svetlanka [38]

Answer:

Total momentum of the system is 378 kg-m/s

Explanation:

It is given that,

Mass of first bumper car, m₁ = 222 kg

Velocity of first bumper car, v₁ = 3.10 m/s (in right)

Mass of other bumper car, m₂ = 165 kg

Velocity of second bumper car, v₂ = -1.88 m/s (in left)

Momentum of the system is given by the product of its mass and velocity. So, the total momentum of this system is given by :

$p=m_1v_1+m_2v_2$

$p=222\ kg\times 3.10\ m/s+165\ kg\times (-1.88\ m/s)$

p = 378 kg-m/s

Hence, the total momentum of the system is 378 kg-m/s

5 0

3 years ago