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creativ13 [48]
2 years ago
6

Define Velocity with an example​

Physics
2 answers:
kolbaska11 [484]2 years ago
8 0

Velocity stands for Displacement w.r.t time

\\ \bull\tt\longmapsto Velocity=\dfrac{Displacement}{Time}

Or

\\ \bull\tt\longmapsto v=\dfrac{ds}{dt}

  • It has units m/s.
asambeis [7]2 years ago
3 0

\pmb{\large{Velocity} }

  • The meaning of velocity of an object can be defined as the rate of change of the object’s position with respect to a frame of reference and time.

  • It might sound complicated but velocity is basically speeding in a specific direction.

  • It is a vector quantity, which means we need both magnitude (speed) and direction to define velocity.

  • The SI unit of it is meter per second (ms-1). 
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A cannon is fired horizontally at 243 m/s off of a 62 meter tall, shear vertical cliff. How far in meters from the base of the c
Alekssandra [29.7K]

Answer:

865.08 m

Explanation:

From the question given above, the following data were obtained:

Initial velocity (u) = 243 m/s

Height (h) of the cliff = 62 m

Horizontal distance (s) =?

Next, we shall determine the time taken for the cannon to get to the ground. This can be obtained as follow:

Height (h) of the cliff = 62 m

Acceleration due to gravity (g) = 9.8 m/s²

Time (t) =?

h = ½gt²

62 = ½ × 9.8 × t²

62 = 4.9 × t²

Divide both side by 4.9

t² = 62/4.9

Take the square root of both side.

t = √(62/4.9)

t = 3.56 s

Finally, we shall determine the horizontal distance travelled by the cannon ball as shown below:

Initial velocity (u) = 243 m/s

Time (t) = 3.56 s

Horizontal distance (s) =?

s = ut

s = 243 × 3.56 s

s = 865.08 m

Thus, the cannon ball will impact the ground 865.08 m from the base of the cliff.

6 0
3 years ago
_____ is the horizontal change between two points on the line.
sattari [20]
The horizontal change between two points on a graph is called the 'run'.

The vertical change between two points is called the 'rise'.
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Suppose you are watching an ice-hockey game with some classmates. As the puck is sliding across the ice at a relatively constant
zavuch27 [327]

Answer:

the answer, the correct one is C

Explanation:

Let's propose the solution of this problem to know which explanation is correct, when the concha stick with the disc is an impulse exercise

                 

             I = ΔP

            ∫ F dt = pf-po

             ∫ F dt = m v_f - m v₀

Therefore, during the time that the contact lasts, a force is applied to the disk, which causes that if the amount of movement increases and therefore its speed increases, when the constant ceases the forces are reduced to zero and the disk no longer changes its momentum following with constant velocity.

When reviewing the answer, the correct one is C

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3 years ago
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