Answer:
6 in
Step-by-step explanation:
The question is incomplete. Here is the complete question.
Juanita and samuel are planning a pizza party. they order a rectangle sheet pizza that measures 21 inches by 36 inches.? they tell the pizza maker not to cut it because they want to cut it themselves. All pieces of pizza must be square with none left over. what is the side length of the largest square pieces into which juanita and samuel can cut the pizza?
First we need to calculate the area of the rectangular pizza.
Area of a rectangle = Length × Breadth
Area of the rectangular pizza= 21×36
Area of the rectangular pizza = 756in²
Next is to equate the area of the rectangle to the area of a square.
Area of a square = L²
Therefore L² = 756
L = √756
L = √36×21
L = √36×√21
L = 6√21
This means that the length if the largest square they can cut is 6in (ignoring the irrational part of the length gotten)
It would be 3/19. Cause you add all and that would be denom.
2y + x = 4
x = -2y + 4
y = x^2 - 6x + 8
y = (-2y + 4)^2 - 6(-2y + 4) + 8
y = (-2y + 4)(-2y + 4) + 12y - 24 + 8
y = 4y^2 - 8y - 8y + 16 + 12y - 24 + 8
y = 4y^2 - 4y
4y^2 - 4y - y = 0
4y^2 - 5y = 0
y(4y - 5) = 0
y = 0 x = -2y + 4
x = -2(0) + 4
x = 4
4y - 5 = 0 x = -2y + 4
4y = 5 x = -2(5/4) + 4
y = 5/4 x = -10/4 + 4
x = -10/4 + 16/4
x = 6/4 which reduces to 3/2
so u have 2 sets of points that will work....
(4,0) and (3/2,5/4) <===
45 plus 15 is 60 so he ran 12 yards so subtract 12 from 60 and your answer is 48
