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3 years ago

Someone help me on this plz

Mathematics

1 answer:

notka56 [123]3 years ago

6 0

The reflection of any point across the x axis is the symmetric of this point, having x axis as axe of symmetry

Let :

A(1,3) its symmetric vs. x axis is A'(1,-3)

B(-1,5) its symmetric vs. x axis is B'(-1,-5)

C(-3,-3) its symmetric vs. x axis is C'(-3,3)

D(-4,-4) its symmetric vs. x axis is D'(-4,4)

Symmetry vs. the x axis keeps abscises the same & change just the sign of y value

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4 years ago

Help me out with these 2 questions for 15 points.

jok3333 [9.3K]

Step-by-step explanation:

The time dilation formula is given by

$F(t) = \dfrac{t}{\sqrt{1-v^2}}$

where t is the time measured by the moving observer and F(t) is the time measured by the stationary earth-bound observer and v is the velocity of the moving observer expressed as a fraction of the speed of light.

a) If the observer is moving at 80% of the speed of light and observes an event that lasts for 1 second, a stationary observer will see the same event occurring over a time period of

$F(t) = \dfrac{1\:\text{s}}{\sqrt{1-(0.8)^2}}$

$\:\:\:\:\:\:\:=\dfrac{1\:\text{s}}{\sqrt{1-(0.8)^2}} =\dfrac{1\:\text{s}}{\sqrt{1-(0.64)}}$

$\:\:\:\:\:\:\:=1.67\:\text{s}$

This means that any event observed by this moving observer will be seen by a stationary observer to occur 67% longer.

b) Given:

t = 1 second

F(t) = 2 seconds

We need to find the speed of the observer such that an event seen by this observer will occur twice as long as seen by a stationary observer. Move the term containing the radical to the left side so the equation becomes

$\sqrt{1-v^2} = \dfrac{t}{F(t)}$