3 years ago

Find the measure of ABD for rectangle ABCD

Mathematics

1 answer:

denis23 [38]3 years ago

4 0

The angle measure is 90°

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The lengths of the bases of the right trapezoid are 9 cm and 18 cm. The length of a longer leg is 15 cm. Find the area of the tr

finlep [7]

Firstly, we will draw figure

now, we will draw a altitude from B to DC that divides trapezium into rectangle and right triangle

because of opposite sides of rectangle ABMD are congruent

so,

DM=AB=9

CM=CD-DM

CM=18-9

CM=9

now, we can find BM by using Pythagoras theorem

$BM=\sqrt{BC^2-CM^2}$

now, we can plug values

we get

$BM=\sqrt{15^2-9^2}$

$BM=12$

now, we can find area of trapezium

$A=\frac{1}{2} (AB+CD)*(BM)$

now, we can plug values

and we get

$A=\frac{1}{2} (9+18)*(12)$

$A=162cm^2$

so, area of of the trapezoid is $162cm^2$ ..........Answer

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yarga [219]

With pleasure. broooooo

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CaHeK987 [17]

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1 year ago

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What is the range of y = (x - 5)^2 – 1?

Setler79 [48]

1. The graph is a parabola.

2. The parabola opens up, because there's no negative number in front of $(x-5)^2$ .

3. The vertext is (5,-1), because of the vertex form.

This means that that -1 will be the least y-value used on the graph and the garph will open up from there.

The range is (-1, infinity) or { y | y > -1 }.

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Simplify:<br> i. (1 + tanA)2 + (1 – tanA)2

zalisa [80]

Answer:

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