Do this, this is the answer
Answer:
nope u took my points so im not helping
The number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
- Since one student runs at a speed of 180 feet per minutes, in time t minutes, he moves a distance of d = 180t.
- Also, the second student runs at a speed of 160 feet per minute, in time t minutes, he moves a distance of d' = 160t.
Since they are initially 10 feet apart, their total distance apart after t minutes is D = d + 10 + d'
D = 180t + 10 + 160t
D = 340t + 10
<h3>Number of minutes before they are 1870 feet</h3>
Making t subject of the formula, we have
t = (D - 10)/340
Since they are 1870 feet apart after t minutes, D = 1870 feet.
t = (D - 10)/340
t = (1870 - 10)/340
t = 1860/340
t = 5.47 minutes
So, the number of minutes that would pass before they were 1870 feet apart is 5.47 minutes
Learn more about minutes of distance apart here
brainly.com/question/8783264
This is what you would do
120 x 17= 2040
Or you could do 12 x 17 then, add a zero to the end of it.
Then you would divid from what you got when you did 120 x 17 by 60
That should give you the answer.
Hope this helps if im not mistaken it should be 34
2040 <span>60 </span>= 34
34 = 340 to the nearest tenth
34 = 34 to the nearest hundredth
34 = 34 to the nearest thousandth
= 0 to the nearest tenth
= 0 to the nearest hundredth
= 0 to the nearest thousandth
Yes you do because you cannot subtract 7 from 6.