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2 years ago

14

Help pls! Giving brainliest!!!!!

1 answer:

RUDIKE [14]2 years ago

3 0

Answer:

$27 = 3 \times 3 \times 3\\\\\frac{1}{27} = \frac{1}{3 \times 3 \times 3} = \frac{1}{3^{3}} = 3^{-3}$

option 3

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What is the soloution to -4x+2=-14

docker41 [41]

Answer:

x = 4

Step-by-step explanation:

subtract 2 from both sides. then -4x is equal to -16. divide by -4 which gives you 4. Hope this helped!

3 0

3 years ago

Read 2 more answers

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

2 years ago

Divide 32.85 by 15 help me work out the problem. please

Arlecino [84]

<em>The answer to 32.85÷15 is 2.19. First, you need to change 32.85 into a whole number. To do that, multiply by powers of ten. There are 2 powers of ten need to turn 32.85 to a whole number. Whatever you do to one side, you must do to the other. So, add 2 zeros to 15. The expression becomes 3,285÷1500. The answer is 2.19</em>

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3 years ago

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Yes

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Matrix L is a 1 ⨯ 8 matrix, matrix M is a 8 ⨯ 8 matrix, matrix N is a 1 ⨯ 1 matrix, and matrix P is a 8 ⨯ 1 matrix. Find the dim

Alenkinab [10]

Answer: fhesfuiewf fjjbeuihr jkfhur

Step-by-step explanation:

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