Answer:
12.7.
Explanation:
∵ pOH = - log[OH⁻].
[OH⁻] = 0.051 M.
∴ pOH = - log[OH⁻] = - log(0.051 M) = 1.29.
∵ pH + pOH = 14.
∴ pH = 14 - pOH = 14 - 1.292 = 12.7.
Answer:
Volume occupied by 55.5 moles of water gas at STP = 1240 Liters.
Explanation:
1st keep in mind that 'volume' in the context of problems like this apply only to the gas phase form of the substance. Water in solid form (ice) or liquid form (liquid water) do not apply. Volume in this case is referred to as 'molar volume' and is a gas occupying 22.4 liters at STP conditions (0°C, 1Atm).
So, if 1 molar volume of water gas (steam) occupies 22.4 Liters at STP, then 55.5 moles of water gas occupies 22.4 Liters/mole x 55.5 moles = 1243.2 Liters, or 1240 Liters (3 sig. figs.). :-)
Answer:
hey listen I'll hate to take the pts and go but I have to do what a man have to do
Answer:
i have no answer for part A
part B
the one that has a 4 can be divided by 2 because reducing
part c
you can determine if an equation is written in the correct way by balancing the equation as if it had not been done already.