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vagabundo [1.1K]
3 years ago
11

Indicate whether each transition is an emission (e) or an absorption (a). Note: the notation '3p 5s' indicates a transition from

a 3p orbital to a 5s orbital.
4p to 6s, 3d to 3p, 8s to 6f, 4p to 4s
Chemistry
1 answer:
kolbaska11 [484]3 years ago
5 0
Can u show picture because without picture I don’t understand the problem u trying to explain
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Today is October 31 and we view or third quarter on what date did we reserve the last new moon
Mrrafil [7]
Answer: March 21

Explanation: March 21
6 0
3 years ago
Vanadium (II) oxide with Iron (III) oxide results in Vanadium (V) oxide and Iron (II) oxide. Balance this equation
evablogger [386]

Answer:

2VO + 3Fe2O3 —> V2O5 + 6FeO

Explanation:

The skeletal equation for the reaction is given below below:

VO + Fe2O3 —> V2O5 + FeO

We can balance the equation above by doing the following:

There are 2 atoms of V on the right side and 1 atom on the left side. It can be balance by putting 2 in front of VO as shown below:

2VO + Fe2O3 —> V2O5 + FeO

Now, we have a total of 5 atoms of O on the left and 6 atoms on the right side. We can balance it by putting 3 in front of Fe2O3 and 6 in front of FeO as shown below:

2VO + 3Fe2O3 —> V2O5 + 6FeO

Now, we can see that the equation is balanced

4 0
3 years ago
How many molecules are in 4 moles of carbon monoxide (CO)?
ladessa [460]

Answer:

A

Explanation:

because number of particle = moles × 6.02 × 10^23

which gives the answer as an A

8 0
3 years ago
điện phân nóng chảy hoàn toàn 14,9 gam muối clorua của 1 kim loại kềm R thu đc 2,24 lít khí . R là kim loại gì ?
prohojiy [21]

Answer:

d

Explanation:

nCl2 = 0,1 -> nRCI = 0,2

M muéi = R + 35,5 = 14,9/0,2

-> R = 39: R la K

4 0
3 years ago
Read 2 more answers
3
Wewaii [24]

Answer: 0.0450 moles of CaCl_2

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}

\text{Number of moles of} CaCl_2=\frac{5.00g}{110.98g/mol}=0.0450moles

Thus there are 0.0450 moles of CaCl_2

6 0
3 years ago
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