20 gram of marble containing 90% calcium carbonate is allowed to react with 50 gram of a concentrated acid containing 36.5% HCl
1 answer:
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Answer: 4.18925 kJ heat is needed to convert 25.0 g of solid ethanol at -135 °C to liquid ethanol at -50°C.
Explanation:
Temperature of Solid
Melting temperature of Solid
Temperature of liquid
Specific heats of solid ethanol = 0.97 J/gK
Specific heats of liquid ethanol = 2.3 J/gK
Heat required to melt the the 25 g solid at 159 K
= 159 K - 138 K = 21 K
Heat required to melt and raise the temperature of upto 223 K
= 223 K - 159 K = 64 K
Total heat to convert solid ethanol to liquid ethanol at given temperature :
(1kJ=1000J)
Hence, 4.18925 kJ of heat will be required to convert 25.0 g of solid ethanol at -135 °C to liquid ethanol at -50°C.
Answer:
The answer is
<h2>1.45 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
From the question
mass of material = 5.01 g
volume = 3.46 mL
The density of the material is
We have the final answer as
<h3>1.45 g/mL</h3>Hope this helps you