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3 years ago

Find the possible dimensions of the sports field given if the width is at least 50yards. need help asap

Mathematics

1 answer:

SashulF [63]3 years ago

8 0

Answer: (If I'm right can I get marked brainiest?)

100

12500

;

√

12500

111.80

yards

Step-by-step explanation:

A football field is a rectangle, so a diagonal line creates 2 right triangles. The formula for the length of the sides of a right triangle is

For this problem, we know

and

, so we just have to find

100

12500

The length of the diagonal is

√

12500

, which is 111.80 yards.

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Given:

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To find:

The equation of the perpendicular bisector of NY.

Solution:

Midpoint point of NY is

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$Midpoint=\left(\dfrac{-11+3}{2},\dfrac{5-3}{2}\right)$

$Midpoint=\left(\dfrac{-8}{2},\dfrac{2}{2}\right)$

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$m=\dfrac{-4}{7}$

Product of slopes of two perpendicular lines is -1. So,

$m_1\times \dfrac{-4}{7}=-1$

$m_1=\dfrac{7}{4}$

The perpendicular bisector of NY passes through (-4,1) with slope $\dfrac{7}{4}$ . So, the equation of perpendicular bisector of NY is

$y-y_1=m_1(x-x_1)$

$y-1=\dfrac{7}{4}(x-(-4))$

$y-1=\dfrac{7}{4}(x+4)$

$y-1=\dfrac{7}{4}x+7$

Add 1 on both sides.

$y=\dfrac{7}{4}x+8$

Therefore, the equation of perpendicular bisector of NY is $y=\dfrac{7}{4}x+8$ .

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