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Sveta_85 [38]
3 years ago
12

Two buses depart two cities moving in the same direction. The speed of the first bus is 54 mph which is 60% of the speed of the

second bus. The faster bus caught up to the other bus one hour and thirty minutes after the departure. will give brainliest
Mathematics
1 answer:
Mama L [17]3 years ago
8 0

Answer:

The second city is 54 miles behind the first city

Step-by-step explanation:

The first bus is assumed to go ahead of the second bus and is moving at 54 mph. The second bus is moving at a speed such as 54 mph is 60% (0.6) of its speed.  

The speed of the second bus is then 54/0.6 = 90 mph

When 1 and a half hour has passed, the first bus has moved a distance of

X_1=54\times 1.5 = 81 miles

The second bus (behind the first bus) has moved

X_2=90\times 1.5 = 135 miles

The problem states they both meet in that time, it can only be possible if the second bus departed a distance 135 - 81 = 54 miles behind the first city

So, the second city is 54 miles behind the first city

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I need help i will give brainiest question in screenshot
Thepotemich [5.8K]

Answer:

ok so first you have to know what a reflectiin along 180 is

) A point P(x,y)P(x,y) is rotated 180180 degrees about the origin, then reflected over the y-axis. What is the resulting image of PP?

My conjecture: (−x,y)(−x,y) but I don't quite agree with it graphically. I'm having trouble with what exactly a 180 degree rotation about the origin simply is.

2) A point P(x,y)P(x,y) is reflected over the y-axis and then rotated 180 degrees about the origin. What is the resulting image?

Is this the same thing as 1?

3) A point A(x,y)A(x,y) is reflected over the line y=xy=x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (−y,x)(−y,x)

4) A point A(x,y)A(x,y) is reflected over the lines y=−xy=−x and then reflected over the y-axis. What is the resulting image of A?

My conjecture: (y,−x)

ok you need to know what thouse meen

Step-by-step explanation:

)If P(x1,y1)P(x1,y1) is rotated angle ϕϕ about O(a,b)O(a,b) to P′(x′,y′)P′(x′,y′)

we have |OP|=|OP′||OP|=|OP′| and |arctanmOP−arctanmOP'|=ϕ|arctan⁡mOP−arctan⁡mOP'|=ϕ

By atan(z)(z) I imply atan2

(2)If P(x1,y1)P(x1,y1) is reflected over L:ax+by+c=0L:ax+by+c=0 and the resulting image of PP is Q(x2,y2)    (1)Q(x2,y2)    (1)

We have R

so i hope thiz helprs you

3 0
3 years ago
What is the answer to this help me please <br>​
liubo4ka [24]

Answer:

australia

Step-by-step explanation:

5 0
2 years ago
1. WRUF 103.7 FM is giving away tickets to a concert. Tim, the general manager of the
Eva8 [605]

Answer:

Kindly check explanation

Step-by-step explanation:

Given that :

Upper level seat = $25

Mid level seat = $40

Number of tickets to give away is at least 25

Budget constraint = $1000

part A: write a system of two inequalities that describe this situation

Number of tickets constraint:

Upper level + mid level ≥ 25

u + m ≥ 25

Cost constraint :

$25u + $40m ≤ $1000

Part B:

Give away 10 upper level seat tickets and 15 mid level seat tickets

8 0
3 years ago
Use two unit multipliers to convert 628 kilometers to centimeters
irina [24]

Using two unit multiplier 628 km is equal to 62800000 cm

<u>Solution:</u>

628 kilometer to centimeter

We will go from kilometers to meters to centimeters.

Start by putting 628 km over 1:

\frac{628 km}{1}

We want to get rid of km and bring in m.

We know that 1000 m = 1 km.

Since km is in the numerator, we will make the  first unit multiplier by putting 1 km in the  denominator and 1000 m in the numerator, so the  km will cancel. So we multiply by the unit multiplier,

\frac{628 km}{1} \times \frac{1000m}{1km}

Now the km's will cancel:

\frac{628}{1} \times \frac{1000m}{1}

Now we want to get rid of m and bring in cm.

We know that 100 cm = 1 m.

Since meter is in the numerator, we will make the  first unit multiplier by putting 1 meter in the  denominator and 100 cm in the numerator, so the  meter's will cancel. So we multiply by the unit  multiplier

\frac{100cm}{1m}

\frac{628}{1} \times \frac{1000m}{1} \times \frac{100cm}{1m}

We cancel the m's and we end up with:

628 \times 1000 \times 100 cm

= 62800000 cm

Thus 628 km is equal to 62800000 cm

5 0
3 years ago
What is the value of a in the equation 3a + b = 54, when b = 9?
sergey [27]
A = 15 3 x 15 + 9 = 54 keep up the good work!
3 0
3 years ago
Read 2 more answers
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