Two buses depart two cities moving in the same direction. The speed of the first bus is 54 mph which is 60% of the speed of the
1 answer:
Answer:
The second city is 54 miles behind the first city
Step-by-step explanation:
The first bus is assumed to go ahead of the second bus and is moving at 54 mph. The second bus is moving at a speed such as 54 mph is 60% (0.6) of its speed.
The speed of the second bus is then 54/0.6 = 90 mph
When 1 and a half hour has passed, the first bus has moved a distance of
= 81 miles
The second bus (behind the first bus) has moved
= 135 miles
The problem states they both meet in that time, it can only be possible if the second bus departed a distance 135 - 81 = 54 miles behind the first city
So, the second city is 54 miles behind the first city
You might be interested in
It’s just the same as if there were no decimal point. but if there isn’t a number in the quotient on the left of the decimal like #15, then you just place a 0 and continue to the next dividend which is 50.
