Two buses depart two cities moving in the same direction. The speed of the first bus is 54 mph which is 60% of the speed of the

Question

4 years ago

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Two buses depart two cities moving in the same direction. The speed of the first bus is 54 mph which is 60% of the speed of the

second bus. The faster bus caught up to the other bus one hour and thirty minutes after the departure. will give brainliest

Mathematics

1 answer:

Mama L [17] · Answer 1 · 2021-12-29T21:52:45+03:00

Answer:

The second city is 54 miles behind the first city

Step-by-step explanation:

The first bus is assumed to go ahead of the second bus and is moving at 54 mph. The second bus is moving at a speed such as 54 mph is 60% (0.6) of its speed.

The speed of the second bus is then 54/0.6 = 90 mph

When 1 and a half hour has passed, the first bus has moved a distance of

$X_1=54\times 1.5$ = 81 miles

The second bus (behind the first bus) has moved

$X_2=90\times 1.5$ = 135 miles

The problem states they both meet in that time, it can only be possible if the second bus departed a distance 135 - 81 = 54 miles behind the first city

So, the second city is 54 miles behind the first city