Two buses depart two cities moving in the same direction. The speed of the first bus is 54 mph which is 60% of the speed of the
1 answer:
Answer:
The second city is 54 miles behind the first city
Step-by-step explanation:
The first bus is assumed to go ahead of the second bus and is moving at 54 mph. The second bus is moving at a speed such as 54 mph is 60% (0.6) of its speed.
The speed of the second bus is then 54/0.6 = 90 mph
When 1 and a half hour has passed, the first bus has moved a distance of
= 81 miles
The second bus (behind the first bus) has moved
= 135 miles
The problem states they both meet in that time, it can only be possible if the second bus departed a distance 135 - 81 = 54 miles behind the first city
So, the second city is 54 miles behind the first city
You might be interested in
A) The constant of proportionality in this proportional relationship is
B) The equation to represent this proportional relationship is y = 0.2x
<h3><u>Solution:</u></h3>Given that,
The amount Naomi pays each month for international text messages is proportional to the number of international texts she sends that month
Therefore,
This is a direct variation proportion
Let "y" be the amount that Naomi pays each month
Let "x" be the number of international texts she sends that month
Therefore,
y = kx -------- eqn 1
Where, "k" is the constant of proportionality
Thus the constant of proportionality in this proportional relationship is:
<em><u>Last month, she paid $3.20 for 16 international texts</u></em>
Therefore,
y = 3.20
x = 16
Thus from eqn 1,
Substitute k = 0.2 in eqn 1
y = 0.2x
The equation would then be y = 0.2x