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2 years ago

Write at least 5 names for 1/4

Mathematics

1 answer:

Elina [12.6K]2 years ago

6 0

1.) One-Fourth
2.) One Quarter
3.) Two- Eighth
I can't think of any more :[ Hope this helped!!

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Question 6

kykrilka [37]

Answer:

m=Y2–Y1/X2–X1

$m = \frac{ - 9 - (6)}{1 - ( - 4)} \\ m = \frac{ - 15}{5} = - 3 \\ y = mx + b \\ y = - 3x + b$

7 0

2 years ago

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Solve the inequality.<br><br> 2 - | 2/5x +3 | > 3/5

meriva

Answer:

Inequality form:

-11< x < -4

Interval Notation:

(-11, -4)

7 0

2 years ago

Which two statements are true?

ANTONII [103]

I think that the answer that is highlighted in blue is correct. I am not sure for this one. But, “both the table and graph are proportional” seems correct.

5 0

2 years ago

Question 15 (1 point)

zloy xaker [14]

Answer:

The value of k is 12.57
Radius of a seventeenth-century cannonball is 2.999 inches which can be rounded off to 3

Step-by-step explanation:

Let s be the surface area and r be the radius

Then according to given statement

s∝r²

Removing the proportionality symbol introduces k, the constant of proportionality

$s = kr^2$

Now

A soap bubble with a 0.75 in. radius has a surface area of approximately 7.07 square inches.

Putting in the equation

$7.07 = k (0.75)^2\\7.07 = k * 0.5625\\k = \frac{7.07}{0.5625}\\k = 12.5688..\\k = 12.57$

The euqation beomes

$s = 12.57r^2$

Putting s = 113.1 in the equation

$113.1 = 12.57r^2\\r^2 = \frac{113.1}{12.57}\\r^2 = 8.99761...\\\sqrt{r^2} = \sqrt{8.9976..}\\r = 2.9996..$

Hence,

The value of k is 12.57
Radius of a seventeenth-century cannonball is 2.999 inches which can be rounded off to 3

4 0

2 years ago

Identify the relationship between 1 and 2

Rufina [12.5K]

Answer:

Step-by-step explanation:

5 0

2 years ago

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