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3 years ago

If three men build a fence in four days,how long would it have taken two men?

Mathematics

1 answer:

vovikov84 [41]3 years ago

4 0

3 men - 4 days |divide 3

1 man - 4/3 day |multiply 2

2 men - 8/3 day

Two men would build this fence in 8/3 day.

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Witch of the following are not correct expressions for slope

AlekseyPX

Answer:

slope can only be showed by the word GRADIENT

Step-by-step explanation:

A slope means how much something is slanting

like if something is Inclined at a specific degree. e. g. This house is inclined at 45° to the road

4 0

3 years ago

A function can be any straight line except a __________line.

mamaluj [8]

Answer: vertical line.

Step-by-step explanation:

Ok we can define a function f(x) as "something" that maps a given input (we usually call the input "x") into a given output (we usually call the output "y")

We have one rule for functions, each input can be mapped into only one output.

So if for example, for a given value x = A.

f(A) = B

and

f(A) = C

This is mapping the input A into two different outputs, then this is not a function.

Now to the question.

If we have a vertical line (parallel to the y-axis)

This line will have only one value of x associated with it, but all the values of y.

This means that this maps one value of the input into infinite outputs, then this can not be a function.

6 0

3 years ago

G(x) = 1-3x when g(10)=

Tomtit [17]

Answer:

g(x)=1-3x

g(10)=1-3(10)=1-30=-29.

5 0

2 years ago

Expand log_1/2(3x^2/2) using the properties and rules for logarithms. Please help.

Naily [24]

Answer:

$\frac{0.1761+2\log(x)}{-0.3010}$

Step-by-step explanation:

Data provided:

$\log_{1/2}(\frac{3x^2}{2})$

now,

we know the properties of log functions as:

1) log(AB) = log(A) + log(B)

2) $\log(\frac{A}{B})$ = log(A) - log(B)

3) log(xⁿ) = n × log(x)

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3x^2)$ - $\log_{1/2}(2)$

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3)+\log_{\frac{1}{2}}(x^2)$ - $\log_{1/2}(2)$

using property 3

$\log_{1/2}(\frac{3x^2}{2})$ = $\log_{1/2}(3)+2\log_{\frac{1}{2}}(x)$ - $\log_{1/2}(2)$

also,

$\log_a(x)=\frac{\log(x)}{\log(a)}$

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)}{\log(\frac{1}{2})}+2\times[\frac{\log(x)}{\log(\frac{1}{2}}]-\frac{\log(2)}{\log(\frac{1}{2})}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)+2\log(x)-\log(2)}{\log(\frac{1}{2})}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{\log(3)+2\log(x)-\log(2)}{\log(1)-log(2)}$

now,

log(1) = 0

log(2) = 0.3010

log(3) = 0.4771

thus,

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{0.4771+2\log(x)-0.3010}{0-0.3010}$

$\log_{1/2}(\frac{3x^2}{2})$ = $\frac{0.1761+2\log(x)}{-0.3010}$

6 0

3 years ago

Read 2 more answers

Please help out will give brainliest

Leno4ka [110]

Answer:

66 cm

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers