9514 1404 393
Answer:
- 2nd force: 99.91 lb
- resultant: 213.97 lb
Step-by-step explanation:
In the parallelogram shown, angle B is the supplement of angle DAB:
∠B = 180° -77°37' = 102°23'
Angle ACB is the difference of angles 77°37' and 27°8', so is 50°29'.
Now, we know the angles and one side of triangle ABC. We can use the law of sines to solve for the other two sides.
BC/sin(A) = AB/sin(C)
AD = BC = AB·sin(A)/sin(C) = (169 lb)sin(27°8')/sin(50°29') ≈ 99.91 lb
AC = AB·sin(B)/sin(C) = (169 lb)sin(102°23')/sin(50°29') ≈ 213.97 lb
The volume of the cone is: A. 213 ft³.
<h3>Volume of a Cylinder and a Cone</h3>
- Volume of cylinder = πr²h.
- Volume of cone = ⅓πr²h.
Given:
radius and height of both the cylinder and the cone are equal.
Volume of Cylinder = 639 ft³
Therefore:
πr²h = ⅓πr²h
This means that volume of cone would be ⅓ of the volume of the cylinder.
Volume of cone = ⅓(639) = 213 ft³
Therefore, the volume of the cone is: A. 213 ft³.
Learn more about volume of cone on:
brainly.com/question/13677400
The answer is C.7/3 pi ft lmk if you want more answers
Value of x is -1
The correct first step to solving the inequality is distributing the -4 into the para thesis
