Based on the elements and charges in Copper (II) Oxalate, CuC₂O₄(s), the solubility in pure water is 1.7 x 10⁻⁴ M.
<h3>What is the solubility of Copper (II) Oxalate in pure water?</h3>
The solubility equilibrium (Ksp) is 2.9 x 10⁻⁸ so the solubility can be found as:
Ksp = [Cu²⁺] [C₂O₄²⁻]
Solving gives:
2.9 x 10⁻⁸ = S x S
S² = 2.9 x 10⁻⁸
S = 1.7 x 10⁻⁴ M
Find out more on solubility at brainly.com/question/23659342.
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The area of a circle is equal to:
r = 1/2 the diameter
1/2 of 14 is 7
7 squared is 49
<em><u>The area is 49π</u></em>
The answer to this question is D.
Yes because they have the same number of sides
Answer:
525 people
Step-by-step explanation:
3000/200=15
You multiply 15 by 35
This equals 525.
