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3 years ago

What is illuminate is it bad

Chemistry

1 answer:

nadya68 [22]3 years ago

8 0

Its a fake myth its alu minate or its for the sign of jews

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The quantity (current times voltage ) is

maksim [4K]

Answer:

Electrical power

Explanation:

An electric circuit can be defined as an interconnection of electrical components which creates a path for the flow of electric charge (electrons) due to a driving voltage.

Generally, an electric circuit consists of electrical components such as resistors, capacitors, battery, transistors, switches, inductors, etc.

The electrical power of an electric circuit can be defined as a measure of the rate at which energy is either produced or absorbed in the circuit.

Mathematically, electrical power is given by the formula;

$Electrical \; power = current * voltage$

This ultimately implies that, the quantity (current times voltage ) is electrical power and it is measured (S.I units) in Watt (W).

7 0

3 years ago

The value of Ksp for PbCl2 is 1.6 ×10-5. What is the lowest concentration of Cl-(aq) that would be needed to begin precipitation

Dovator [93]

Answer:

0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.

Explanation:

Concentration of lead nitarte = $[Pb(NO_3)_2]=0.010 M$

$Pb(NO_3)_2(aq)\rightleftharpoons Pb^{2+}(aq)+2NO_{3}^{-}(aq0$

1 Mole of lead nirate gives 1 mole of lead ion.

Concentration of lead ion in the solution = $1\times 0.010 M= 0.010 M$

$Pb(Cl)_2(aq)\rightleftharpoons Pb^{2+}(aq)+2Cl^{-}(aq0$

Concentration of chloride ions = $[Cl^-]$

The value of $K_{sp} for [tex]PbCl_2= 1.6\times 10^{-5}$

$K_{sp}=[Pb^{2+}][Cl^{-}]^2$

$1.6\times 10^{-5}=0.010 M\times [Cl^{-}]^2$

$[Cl^-]=0.04 M$

0.04 M is the lowest concentration of chloride ions that would be needed to begin precipitation.

3 0

4 years ago

7. The grid in a triode is kept negatively charged to prevent A. electrons from escaping from the tube containing the triode. B.

romanna [79]

Answer:

A. Electrons from escaping from the tube containing the triode.

Explanation:

5 0

3 years ago

In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)20) + 2 NaBr jaPbBr2s 2 NaNO3a) The mo

Shtirlitz [24]

Pb(NO3)2 + 2 NaBr ------> PbBr2 + 2 NaNO3
2 mol 2 mol

M(NaBr)= 102 g/mol
M(NaNO3) = 85 g/mol

1) 244g NaNO3 *1 mol NaNO3/85 g NaNO3 = 244/85 mol NaNO3

2) Pb(NO3)2 + 2 NaBr ------> PbBr2 + 2 NaNO3
2 mol 2 mol
x mol 244/85 mol

x=(2 mol* 244/85 mol )/2 mol = 244/85 mol NaBr

3) 244/85 mol NaBr*102g NaBr/1 mol = (244*102/85) g NaBr =292.8 g NaBr

8 0

3 years ago

What is the IUPAC name?

Anastasy [175]

International Union of Pure and Applied Chemistry

4 0

3 years ago