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Alina [70]
3 years ago
15

In the following reaction, how many grams of NaBr will produce 244 grams of NaNO3? Pb(NO3)20) + 2 NaBr jaPbBr2s 2 NaNO3a) The mo

lar mass of NaBr is 102 9 grams and that of NäNO is 85 grams
Chemistry
1 answer:
Shtirlitz [24]3 years ago
8 0
<span> Pb(NO3)2 + 2 NaBr ------> PbBr2 + 2 NaNO3
                     2 mol                             2 mol

M(NaBr)= 102 g/mol
M(NaNO3) = 85 g/mol

1) 244g NaNO3 *1 mol NaNO3/85 g NaNO3 = 244/85 mol NaNO3

2)</span> Pb(NO3)2 + 2 NaBr ------> PbBr2 + 2 NaNO3
                     2 mol                             2 mol<span>
                     x mol                             </span>244/85 mol 
<span>
x=(2 mol*</span> 244/85 mol )/2 mol =  244/85 mol NaBr
<span>
3) </span> 244/85 mol NaBr*102g NaBr/1 mol = (244*102/85) g NaBr =292.8 g NaBr<span>
              

</span>
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3 years ago
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Answer:

The answer is

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Explanation:

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From the question

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