The molarity of Barium Hydroxide is 0.289 M.
<u>Explanation:</u>
We have to write the balanced equation as,
Ba(OH)₂ + 2 HNO₃ → Ba(NO₃)₂ + 2 H₂O
We need 2 moles of nitric acid to react with a mole of Barium hydroxide, so we can write the law of volumetric analysis as,
V1M1 = 2 V2M2
Here V1 and M1 are the volume and molarity of nitric acid
V2 and M2 are the volume and molarity of Barium hydroxide.
So the molarity of Ba(OH)₂, can be found as,
= 0.289 M
Hi there!
A mole is a type of unit measurement for an amount of a substance like in your cast, salt.
One mole of salt will be the equivalent to 58 grams
Hope this helped!~
Charles law gives the relationship between temperature and volume of gases. It states that the volume of gas is directly proportional to temperature at constant pressure.
V / T = k
where V - volume and T - temperature in Kelvin and k - constant
where parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
T1 - 20 °C + 273 = 293 K
substituting these values in the equation
T = 586 K
temperature in celsius = 586 K - 273 = 313 °C
new temperature is 313 °C
Simply put, Potential energy is the "build up". If I had a ball on the top a 5ft slide, it would have potential energy, as long as it hasn't slid down yet.
If I had another ball on a 10ft slide, it would have twice the potential energy the first ball had.
What comes next is kinetic energy, which is the energy used when the object is moving, like the ball as it goes down the slide. The faster it moves, the more kinetic energy.
Basically, <em>Potential</em> is the "build up" but it does not, I repeat does not move.
<em>Kinetic</em> energy is the use of the "build up" through movement.
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This problem is providing information about the initial mass of mercury (II) oxide (10.00 g) which is able to produce liquid mercury (8.00 g) and gaseous oxygen and asks for the resulting mass of the latter, which turns out to be 0.65 g after doing the corresponding calculations.
Initially, it is given a mass of 10.00 g of the oxide and 1.35 g are left which means that the following mass is consumed:
Now, since 8.00 grams of liquid mercury are collected, it is possible to calculate the grams of oxygen that were produced, by considering the law of conservation of mass, which states that the mass of the products equal that of the reactants as it is nor destroyed nor created. In such a way, the mass of oxygen turns out to be:
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