Answer:
C3H6O
Explanation:
Data obtained from the question. This includes:
Carbon (C) = 0.62069 g
Hydrogen (H) = 0.103448 g
Oxygen (O) = 0.275862 g
The empirical formula can be obtained as follow:
Step 1:
Divide by their molar mass.
C = 0.62069 / 12 = 0.0517
H = 0.103448 / 1 = 0.103448
O = 0.275862 / 16 = 0.0172
Step 2:
Divide by the smallest number.
C = 0.0517 / 0.0172 = 3
H = 0.103448 / 0.0172 = 6
O = 0.0172 / 0.0172 = 1
Step 3:
Writing the empirical formula.
The empirical formula is C3H6O
Answer:
Chemical reactions involve breaking chemical bonds between reactant molecules
Explanation:
In a chemical reaction, the atoms and molecules that interact with each other are called reactants. ... No new atoms are created, and no atoms are destroyed. In a chemical reaction, reactants contact each other, bonds between atoms in the reactants are broken, and atoms rearrange and form new bonds to make the products
First, you need to find the mass of 1 mol of sugar. Mass, or molar mass, can simply be found by adding the masses of the individual elements. These are given to you on the periodic table.
12 x 12.011 grams (molar mass of Carbon) = 144.132 g
22 x 1.008 grams (molar mass of Hydrogen) = 22.176 g
11 x 15.999 grams (molar mass of Oxygen) = 175.989 g
Add all of the pieces together.
144.132 g + 22.176 g + 175.989 g = 342.297 grams
So, if one mole has 342.297 grams, then 7.35 of that amount will be your answer.
342.297 g/mol x 7.35 mol = 2,515.88 grams
Answer:
This is a conversion factor
Answer:
The bolts will run out first, so these will limit how much product can be formed.
(option C is correct)
Explanation:
Step 1: Data given
Number of bolts = 5
Number of nuts = 12
ratio N:B = 2:1
Step 2
Since the ratio N:B is 2:1 we have 2 nuts for each bolt
When we have 2 bolts we have 4 nuts
When we have 3 bolts we have 6 nuts
When we have 4 bolts we have 8 nuts
When we have 5 bolts we have 10 nuts
We don't have more bolts, but there are still 2 nuts left. This means the bolts will run out first, so these will limit how much product can be formed.
(option C is correct)
