Answer:
Abel receives $60, and Cedric receives $120
Step-by-step explanation:
Let Abel's share = A
Let Cedric's share = C
we are given the following
A + C = 180 - - - - - (1) (Abel and Cedric will share a total of $180)
(Abel will receive half as much as Cedric. )
from equation 2:

putting this value of C in eqn (3) into eqn (1)
A + (2A) = 180
3A = 180
∴ A = 180 ÷ 3 = 60
to find C, let us replace the value of A in eqn (3) with 60
C = 2A - - - - (3)
C = 2 × 60
C = 120
Therefore, Abel receives $60, and Cedric receives $120
Answer:
<h2>The value of y is <u>0.5</u>, so the answer is <u>C</u>.</h2>
Step-by-step explanation:
Find first the constant of variation.
Given: x = 3, y = 4
Find: k = ?
Formula:

Solution:

Then, find the value of y in the third box.
Given: x = 24, k = 12
Find: y = ?
Formula:

Solution:

(a+15.25)=x cost of each tree
(a•15)=110 cost of all the shrub
(x•5)= 101.25 cost of all trees
110+101.25= 211.25
equatiin all together
[(a+15.25)×5]+(a×15)=211.25
Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.