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ExtremeBDS [4]
3 years ago
8

As the moon revolves around the earth,it also rotated on its axis why is that the same side of the moon is always visible from e

arth?
Physics
2 answers:
blsea [12.9K]3 years ago
8 0

Answer:

The answer is accually D.  The speed of the Moon's rotation keeps the same side always facing Earth.

Explanation:

Alina [70]3 years ago
7 0

Answer:

Explanation:

Our lunar companion rotates while it orbits Earth. It's just that the amount of time it takes the moon to complete a revolution on its axis is the same it takes to circle our planet — about 27 days. As a result, the same lunar hemisphere always faces Earth.

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Ocean waves are hitting a beach with a frequency of 0.100 Hz. Their average wavelength is 15.0 m. What is their average speed?
den301095 [7]

Answer:

Average speed=1.5 m/s

Frequency of pendulum=93.75Hz

Explanation:

We are given

Frequency, f=0.100Hz

Average wavelength =\lambda=15m

Speed of pendulum, v=30m/s

Wavelength, \lambda'=0.32m

We have to find the average speed and frequency of pendulum.

We know that

Speed,v=\lambda f

Using the formula

Average speed,v=15\times 0.1=1.5m/s

Hence, the average speed =1.5m/s

Frequency, f=\frac{v}{\lambda'}

Using the formula

f=\frac{30}{0.32}

f=93.75Hz

Hence, the frequency of a pendulum=93.75Hz

6 0
2 years ago
A car travels 20 km South, then turns and travels 30 km East? What is the total displacement?
Ne4ueva [31]

Answer:

Explanation:36.05 km

Given

First car travels r_1=20\ km South

then turns and travels r_2=30\ km east

Suppose south as negative y axis and east as positive x axis

So, r_1=-20\hat{j}

r_2=30\hat{i}

Displacement is the shortest between initial and final point

Dispalcement=r=r_1+r_2

Displacement=-20\hat{j}+30\hat{i}

Displacement=30\hat{i}-20\hat{j}

Magnitude =\sqrt{30^2+(-20)^2}

Magnitude=36.05\ km

4 0
3 years ago
Two neutral metal spheres on wood stands are touching. A negatively charged rod is held directly above the top of the left spher
Paha777 [63]

Answer:

The right sphere is negatively charged, the left sphere is charged positively.

Explanation:

When a negatively charged rod is held above the top of left sphere, the rod will attract positive charges and repel negative charges. As the sphere are initially touching each other so positive charges from the both spheres will moves toward the rod. When we separate the spheres positive charges from right sphere have already moved toward the rod i.e. left sphere, creating a deficiency of positive charges in the right sphere and excessiveness of positive charges in left sphere , hence the right sphere will remain negatively charged and left sphere will remain positively charged.

4 0
3 years ago
A student initially 10.0 m East of his school walks 17.5 m West. The magnitude of the student's displacement, relative to the sc
Fantom [35]

Answer:

1. 7.5 m

2. towards west side

explanation:

I hope it will help you

3 0
2 years ago
Water flows through a horizontal pipe of varying cross-section. In the first section, the cross-sectional area is 10 cm2 and flo
Stels [109]

Answer:

(a) the flow speed of the second section is 11 m/s

(b) the pressure of the second section is 6.33 x 10⁴ Pa

Explanation:

Given;

flow rate in the first section, Q₁ = 2750 cm³/sec

area of the first cross section, A₁ = 10 cm²

pressure in the first cross section, P₁ = 1.2 x 10⁵ Pa

area of the second section, A₂ = 2.5 cm²

(a) the flow speed of the second section (V₂)

Apply continuity equation;

Q₁ = Q₂

Q₁ = A₂V₂

V₂ = Q₁ / A₂

V₂ = (2750) / (2.5)

V₂ = 1100 cm/s = 11 m/s

(b) the pressure of the second section (P₂)

Apply Bernoulli's equation;

P₁ + ¹/₂ρV₁² = P₂ + ¹/₂ρV₂²

where;

ρ is density of water = 1000 kg/m³

V₁ is the speed of water in the first section;

Q₁ = A₁V₁

V₁ = Q₁ / A₁

V₁ = (2750) / (10)

V₁ = 275 cm/s = 2.75 m/s

P₂ = P₁ + ¹/₂ρV₁² - ¹/₂ρV₂²

P₂ = P₁ + ¹/₂ρ(V₁² - V₂²)

P₂ = 1.2 x 10⁵ Pa + ¹/₂ x 1000 (2.75² - 11²)

P₂ = 1.2 x 10⁵ Pa + 500(-113.438)

P₂ = 1.2 x 10⁵ Pa - 0.567  x 10⁵ Pa

P₂ = 0.633 x 10⁵ Pa

P₂ = 6.33 x 10⁴ Pa

8 0
2 years ago
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