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horsena [70]
3 years ago
5

The force of gravity between two objects depends on ___________.

Physics
1 answer:
murzikaleks [220]3 years ago
4 0
The answer is D. the mass of the two objects and the distance between them
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A man hits a 50 grams golf ball such that it leaves the tee at an angle of 40o with the horizontal and strikes the ground at the
lukranit [14]

Answer:

Explanation:

Range of projectile R = 20 m

formula of range

R = u² sin2θ / g

u is initial velocity , θ is angle of projectile

putting the values

20 = u² sin2x 40 / 9.8

u² = 199

u = 14.10 m /s

At the initial point

vertical component of u

= u sin40 = 14.1 x sin 40

= 9.06 m/s

Horizontal component

= u cos 30

At the final point where the ball strikes the ground after falling , its speed remains the same as that in the beginning .

Horizontal component of velocity

u cos 30

Vertical component

= - u sin 30

= - 9.06 m /s

So its horizontal component remains unchanged .

change in vertical component = 9.06 - ( - 9.06 )

= 18.12 m /s

change in momentum

mass x change in velocity

= .050 x 18.12

= .906 N.s

Impulse = change in momentum

= .906 N.s .

3 0
4 years ago
The specific heat of iron is 0.45j/gk. The amount of heat needed to raise the temperature of the 12 g of iron by exactly 15k?
labwork [276]

Answer:

81 J.

Explanation:

From the question given above, the following data were obtained:

Specific heat capacity (C) = 0.45 J/gK.

Temperature change (ΔT) = 15 K

Mass = 12 g

Heat required (Q) =?

The heat required to raise the temperature of iron can be obtained as illustrated below:

Q = MCΔT

Q = 12 × 0.45 × 15

Q = 81 J

Therefore, the heat required to raise the temperature of the iron is 81 J.

8 0
3 years ago
S When an uncharged conducting sphere of radius a is placed at the origin of an x y z coordinate system that lies in an initiall
telo118 [61]

The sphere has a constant potential. It is the electric field.

E = V_{0} = 0

In the sphere, then

E_{x} = 0,  E_{y}=0,   E_{z}=0

Outside the sphere, then

V = V_{0} - E_{0}z + \frac{E_{0}a^{3}z}{(x^{2} +y^{2} + z^{2})^{3/2}   }

The elements of the electric field include

E_{x} =\frac{3E_{0}a^{3}xy}{(x^{2} +y^{2} +z^{2})^{5/2}}\\E_{y} = \frac{3E_{0}a^{3}xz}{(x^{2} +y^{2}+z^{2})^{5/2}}

Which becomes,

=E_{0} (1-\frac{a^{3}}{x^{2} +y^{2}+z^{2})^{3/2}}+\frac{3a^{3}z^{2}}{(x^{2} +y^{2}+z^{2})^{5/2}})

<h3>In a consistent electric field, is force constant?</h3>

Similar to an ordinary object in the uniform gravitational field near the Earth's surface, a charged item in a uniform electric field experiences a constant force and consequently experiences a uniform acceleration. The vector cross product of p and E determines the torque's direction.

If the charge is positive, the force either moves in the same direction as E or in the opposite direction (if charge is negative).

A torque is experienced by an electric dipole (p) in an even electric field (E). The vector cross product of p and E determines the torque's direction.

To learn more about uniform electric field, visit

brainly.com/question/17426130

#SPJ4

5 0
2 years ago
Help me, please
Mars2501 [29]
Wish I could help you you rock
6 0
3 years ago
What is the atmospheric pressure 1.00 km above the surface of Venus? Express your answer in Earth-atmospheres.
EleoNora [17]

Below is an attachment containing the solution.

4 0
3 years ago
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