Answer:
Option (4)
Explanation:
There are two types of collision.
Perfectly elastic collision: the collision in which the momentum and kinetic energy is conserved. There is no loss of energy in other forms of energy.
Perfectly plastic collision: The collision in which the momentum is conserved and kinetic energy is not conserved. The two bodies stick after the collision.
Here, the bullet hits the block and then embedded in the block, it is the example of plastic collision.
Answer:
h=17357.9m
Explanation:
The atmospheric pressure is just related to the weight of an arbitrary column of gas in the atmosphere above a given area. So, if you are higher in the atmosphere less gass will be over you, which means you are bearing less gas and the pressure is less.
To calculate this, you need to use the barometric formula:
![P=P_0e^{-\frac{Mg}{RT}h}](https://tex.z-dn.net/?f=P%3DP_0e%5E%7B-%5Cfrac%7BMg%7D%7BRT%7Dh%7D)
Where R is the gas constant, M the molar mass of the gas, g the acceleration of gravity, T the temperature and h the height.
Furthermore, the specific gas constant is defined by:
![R_{H_2}=\frac{R}{M}](https://tex.z-dn.net/?f=R_%7BH_2%7D%3D%5Cfrac%7BR%7D%7BM%7D)
Therefore yo can write the barometric formula as:
![P=P_0e^{-\frac{g}{R_{H_2}T}h}](https://tex.z-dn.net/?f=P%3DP_0e%5E%7B-%5Cfrac%7Bg%7D%7BR_%7BH_2%7DT%7Dh%7D)
at the surface of the planet (h =0) the pressure is ![P_0[\tex]. The pressure at the height requested is half of that:[tex]P=\frac{P_0}{2}](https://tex.z-dn.net/?f=P_0%5B%5Ctex%5D.%20The%20pressure%20at%20the%20height%20requested%20is%20half%20of%20that%3A%3C%2Fp%3E%3Cp%3E%5Btex%5DP%3D%5Cfrac%7BP_0%7D%7B2%7D)
applying to the previuos equation:
![\frac{P_0}{2} =P_0e^{-\frac{g}{R_{H_2}T}h}](https://tex.z-dn.net/?f=%5Cfrac%7BP_0%7D%7B2%7D%20%3DP_0e%5E%7B-%5Cfrac%7Bg%7D%7BR_%7BH_2%7DT%7Dh%7D)
solving for h:
h=17357.9m
Answer: D) dedicate as many hours as needed to the work.
Explanation:
edge 2020