All categories

3 years ago

Car moves 5km East,3km south,2km West, 1km north find displacement(please show me the way)

Physics

2 answers:

ddd [48]3 years ago

4 0

Answer:

3.605551275463989

Explanation:

solve using Pythagorean theorem

Helen [10]3 years ago

3 0

Answer:

heyy babe

want to have fun?

You might be interested in

Describe the relationship between the length and period of a pendulum in the language of direct proportions

Wittaler [7]

The period of the pendulum is directly proportional to the square root of the length of the pendulum

Explanation:

The period of a simple pendulum is given by the equation

$T=2\pi \sqrt{\frac{L}{g}}$

where

T is the period

L is the length of the pendulum

g is the acceleration of gravity

From the equation, we see that when the length of the pendulum increases, the period of the pendulum increases as the square root of L, $T\propto \sqrt{L}$ . This means that

The period of the pendulum is directly proportional to the square root of the length of the pendulum

From the equation, we also notice that the period of a pendulum does not depend on its mass.

#LearnwithBrainly

3 0

3 years ago

A speedometer of a car reads a constant 60 km per hour while negotiating a curve. Which of the following could NOT be true?

seraphim [82]

Answer:

Explanation:

3 0

3 years ago

What will be the displacement of this spring if the load is 4n with a constant of 5n\m

nikdorinn [45]

As we have formula for mass spring system

F= kx ( where k is spring constant , x is displacement , F is the force acting due to load)

To find =x

So x=F/k

x= (4N) / (5N/m)

x= 0.8 m

3 0

3 years ago

Speed is the ratio of the distance an object moves to (1 point)the amount of time needed to travel the distance.

Dennis_Churaev [7]

a) the distance an object moves to the amount of time needed to travel the distance.

i hope this helps :3

6 0

4 years ago

A normal human heart, beating about once per second, creates a maximum 4.00 mV 4.00 mV potential across 0.250 m 0.250 m of a per

ElenaW [278]

Answer:

1) maximum electric field strength = 0.016 V/m

2)maximum magnetic field strength = 5.33 x 10^(-11) T

3) wavelength = 3 x 10^(8)m

Explanation:

A) We are given;

Frequency (f) = 1 Hz

Maximum Potential ΔV = 4 mV = 4 x 10^(-3) V

Length; d = 0.25 m

Now, maximum potential formula is given as;

ΔV = E_o•d

Where E_o is maximum electric field strength.

Thus,

E_o= ΔV/d = (4 x 10^(-3))/0.25 = 0.016 V/m

B) The maximum magnetic field strength is given by;

B_o = E_o/c

Where;

c is speed of light = 3 x 10^(8)

B_o is maximum magnetic field strength

Thus,

B_o = 0.016/(3 x 10^(8)) = 5.33 x 10^(-11) T

C) Speed of any electromagnetic wave is given by;

c = fλ

Where;

f is frequency

λ is wavelength

c is speed of light = 3 x 10^(8)

Thus, making λ the subject,

λ = c/f

λ = (3 x 10^(8))/1 = 3 x 10^(8)m

8 0

4 years ago

Car moves 5km East,3km south,2km West, 1km north find displacement(please show me the way)​

Car moves 5km East,3km south,2km West, 1km north find displacement(please show me the way)