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2 years ago

6

Car moves 5km East,3km south,2km West, 1km north find displacement(please show me the way)

2 answers:

ddd [48]2 years ago

4 0

Answer:

3.605551275463989

Explanation:

solve using Pythagorean theorem

Helen [10]2 years ago

3 0

Answer:

heyy babe

want to have fun?

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The earth's radius is 6.37×10^6m; it rotates once every 24 hours. with the angular speed of 7.3 x 10^-5 what is the speed of a p

alexira [117]

The speed of the earth's surface located at 2/3 of the length of the arc between the pole which measure from the equator is 232.5 m/s.

Solution:
So the givens are, earth's radius = 6.37X10^6m, and the angular distance from the pole is 90 degrees. So 60 degrees is the 2/3.

r = 6.37x10^6 * cos(60) = 3.185x10^6m
since v = wr
v = 7.3x10^-5 * 3.185x10^6

v - 232.5 m/s

6 0

2 years ago

How long does it take electrons to get from the car battery to the starting motor? Assume the current is 143 A and the electrons

Ostrovityanka [42]

Answer

the concentration of electron/ volume (n) = 8.5 × 10²⁸ /m³

the drift velocity of electron

$v = \dfrac{I}{neA}$

$v = \dfrac{143}{8.5\times 10^{28}\times 1.6\times 10^{-19}\times 40.2 \times 10^{-6}}$

v = 2.615 × 10⁻⁴ m/s

time require is

$t=\dfrac{L}{v}$

$t=\dfrac{0.845}{2.615\times 10^{-4}}$

t = 3231.35 s

5 0

3 years ago

प्रकाशको आवर्तनको परिभाषा लेख्नुहोस् । कन्भेक्स ऐनाको अगाडि तपाई उभियौ भने तपाईको कस्तो आकृति बन्छ, लेख्नर

allochka39001 [22]

A diagram alright of the

4 0

2 years ago

What could we call the<br> grocery store?<br> A. Linear motion<br> B. Reference point<br> C. Rotary

Roman55 [17]

Reference point

Explanation:

I am not sure

8 0

2 years ago

A bug on the surface of a pond is observed to move up and down a total vertical distance of 6.5 cm , from the lowest to the high

m_a_m_a [10]

Answer:

factor that bug maximum KE change is 0.52284

Explanation:

given data

vertical distance = 6.5 cm

ripples decrease to = 4.7 cm

solution

We apply here formula for the KE of particle that executes the simple harmonic motion that is express as

KE = (0.5) × m × A² × ω² .................1

and kinetic energy is directly proportional to square of the amplitude.

so

$\frac{KE2}{KE1} = \frac{A2^2}{A1^2}$ .............2

$\frac{KE2}{KE1} = \frac{4.7^2}{6.5^2}$

$\frac{KE2}{KE1}$ = 0.52284

so factor that bug maximum KE change is 0.52284

5 0

2 years ago