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AleksAgata [21]
3 years ago
14

1.80 kJ of heat is added to a slug of gold and a separate 1.80 kJ of heat is added to a slug of manganese. The heat capacity of

the gold slug is 149J/°C while the heat capacity of the manganese slug is 505 J/°C. If the slugs are each originally at 25.00°C, what is the final temperature of each slug?
Physics
1 answer:
Svetlanka [38]3 years ago
7 0

Answer:

final temperature of  slug of gold is 37°C

final temperature of  slug of manganese is 28.56°C

Explanation:

Hello! To solve this problem we must take into account the concept of heat capacity, this is defined as the ratio between energy and temperature rise.

In other words it is the amount of energy that is required to increase a temperature degree.

Taking into account the above we infer the following equation

where  

C=heat capacity

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PLEASE HELP
Sergeu [11.5K]

The vertical component of the initial velocity is v_0_y = \frac{y}{t} + \frac{1}{2} gt

The horizontal component of the initial velocity is v_0_x = \frac{x}{t}

The horizontal displacement when the object reaches maximum height is X = \frac{xy}{gt^2} + \frac{x}{2}

The given parameters;

the horizontal displacement of the object, = x

the vertical displacement of the object, = y

acceleration due to gravity, = g

time of motion, = t

The vertical component of the initial velocity is given as;

y = v_0_yt - \frac{1}{2} gt^2\\\\v_0_yt = y + \frac{1}{2} gt^2\\\\v_0_y = \frac{y}{t} + \frac{1}{2} gt

The horizontal component of the initial velocity is calculated as;

x = v_0_xt\\\\v_0_x = \frac{x}{t}

The time to reach to the maximum height is calculated as;

T = \frac{v_f_y -v_0_y}{-g} \\\\T = \frac{-v_0_y}{-g} \\\\T = \frac{v_0_y}{g} \\\\T =  \frac{1}{g}  (v_0_y)\\\\T = \frac{1}{g} (\frac{y}{t} + \frac{1}{2} gt)\\\\T = \frac{y}{gt} + \frac{1}{2} t

The horizontal displacement when the object reaches maximum height is calculated as;

X= v_0_x \times T\\\\X= \frac{x}{t} \times (\frac{y}{gt} + \frac{1}{2} t)\\\\X = \frac{xy}{gt^2} + \frac{x}{2}

Learn more here: brainly.com/question/20689870

8 0
3 years ago
PLEASE ITS AN Emergency IF ITS RIGHT I WILL GIVE BRAINLIEST
n200080 [17]

Answer:

all of those are pisitions

Explanation:

6 0
3 years ago
Which energy transformation occurs in the core of a nuclear reactor?
romanna [79]
The correct answer among the choices given is option B. The energy transformation that occurs in the core of a nuclear reactor is from nuclear energy to thermal energy. In a power plant nuclear fission which involves nuclear energy to heat up water around it. This part is  the core of the process.
5 0
3 years ago
Suppose the sphere is electrically neutral. Is it attracted to
Elden [556K]

Answer:

No, it is not attracted.

Explanation:

If any sphere is electrically neutral it is not attracted. The materials which are attracted by magnet are called magnetic material whereas which are not attracted are called non magnetic material. Sphere made up of non magnetic materials such as glass, wood, paper will not attracted weather is kept near north pole or near south pole.

8 0
3 years ago
HELP BRANLIEST
Vsevolod [243]

Explanation:

- Newton's first law of motion:

"An object at rest (or in uniform motion) remains at rest (or in uniform motion) unless acted upon an unbalanced force

In this situation, we can apply Newton's first law to the keys of the keyboard that are not hit by the fingers of the man. In fact, as no force act on the keys, they remain at rest.

- Newton's second law of motion:

"The acceleration experienced by an object is proportional to the net force exerted on the object; mathematically:

F=ma

where F is the net force, m is the mass of the object, and a its acceleration"

In this case, we can apply Newton's second law to the keys of the keyboard that are hit by the man: in fact, as they are hit, they experience a downward force, and therefore they experience a downward acceleration.

"Newton's third law of motion:

"When an object A exerts a force on an object B (action force), then object B exerts an equal and opposite force on object A (reaction force)"

Here We can apply Newton's third law to the pair of objects finger-key: in fact, as the finger apply a force on the key (action force), then the key exerts a force back on the finger (reaction force), equal and opposite.

3 0
3 years ago
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