1.80 kJ of heat is added to a slug of gold and a separate 1.80 kJ of heat is added to a slug of manganese. The heat capacity of
1 answer:
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Answer:
the thermal energy generated in the loop =
Explanation:
Given that;
The length of the copper wire L = 0.614 m
Radius of the loop r =
r =
r = 0.0977 m
However , the area of the loop is :
Change in the magnetic field is
Then the induced emf e =
e =
e = 2.74 × 10⁻³ V
resistivity of the copper wire Ω m
diameter of the wire = 1.08 mm
radius of the wire = 0.54 mm = 0.54 × 10⁻³ m
Thus, the resistance of the wire R =
R =
R = 1.13× 10⁻² Ω
Finally, the thermal energy generated in the loop (i.e the power) =
=
=
Answer:
10 m/s
Explanation:
Kinetic energy= mv² where m is mass and v is velocity.
We have to make v the subject so we should rearrange the equation
K=mv²
v²= (use algebra)
v²= 7/0.5×0.140
v²=100
v=√100
v=10 m/s
We can confirm this by using the kinetic energy formula.
K=×0.140×10²
K= 7 J
Hence it is proved that velocity is 10 m/s