2 years ago

How many combinations of 3 students can a teacher choose from 32 students? A. 96 B. 4960 C. 29,760 D. 32,768

Mathematics

2 answers:

rusak2 [61]2 years ago

5 0

${32\choose3}=\frac{32!}{3!*(32-3)!}=\frac{30*31*32}{6}=4960$

Allisa [31]2 years ago

3 0

$\frac{32*31*30}{3*2*1}$

The answer is: $\frac{29760}{6}$ or $4960$

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