3 years ago

How many combinations of 3 students can a teacher choose from 32 students? A. 96 B. 4960 C. 29,760 D. 32,768

Mathematics

2 answers:

rusak2 [61]3 years ago

5 0

${32\choose3}=\frac{32!}{3!*(32-3)!}=\frac{30*31*32}{6}=4960$

Allisa [31]3 years ago

3 0

$\frac{32*31*30}{3*2*1}$

The answer is: $\frac{29760}{6}$ or $4960$

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Katelyn does not have enough money to buy items she likes.

Step-by-step explanation:

Amount Katelyn had = $205

Price of one sweater = $48

Price of 2 sweaters = 2*48 = $96

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Price of four pairs of pants = 34*4 = $136

Total price = Price of sweaters + price of pairs of pants

Total price = $96+136$

$Total\ price= \$232$

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Sales tax = $\frac{6.5}{100}*232$

$Sales\ tax=\frac{1508}{100}\\Sales\ tax=15.08\ Dollars$

Total amount = Total amount of items + sales tax

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Total amount = 247.08 Dollars

Therefore,

Katelyn does not have enough money to buy items she likes.

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Step-by-step explanation:

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