3 years ago

How many combinations of 3 students can a teacher choose from 32 students? A. 96 B. 4960 C. 29,760 D. 32,768

2 answers:

5 0

${32\choose3}=\frac{32!}{3!*(32-3)!}=\frac{30*31*32}{6}=4960$

3 0

$\frac{32*31*30}{3*2*1}$

The answer is: $\frac{29760}{6}$ or $4960$

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diamong [38]

I am pretty sure R is -19 meters and N is -7 and A is 476 AD

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Ghella [55]

The best answer would be
2.4 x 10 ^6
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Vedmedyk [2.9K]

Step-by-step explanation:

$\frac{5}{4} = \frac{x}{6} \\ 4x = 30 \\ x = 7.5$

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Sedbober [7]

Answer:

x=30

Step-by-step explanation:

supplementary= 180

so 180-150=30

x=30

hope this helps

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3 years ago

diamong [38]

18,225 :) have a nice day!

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2 years ago