Factorise x^2 + 9x + 20
1 answer:
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Answer:
Step-by-step explanation:
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Answer:
g'(0) = 0
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
- Left to Right
<u>Algebra I</u>
- Function Notation
<u>Pre-Calculus</u>
- Unit Circle
<u>Calculus</u>
- Derivatives
- Derivative Notation
- The derivative of a constant is equal to 0
- Derivative Property:
- Trig Derivative:
Step-by-step explanation:
<u>Step 1: Define</u>
g(x) = 8 - 10cos(x)
x = 0
<u>Step 2: Differentiate</u>
- Differentiate [Trig]: g'(x) = 0 - 10[-sin(x)]
- Simplify Derivative: g'(x) = 10sin(x)
<u>Step 3: Evaluate</u>
- Substitute in <em>x</em>: g'(0) = 10sin(0)
- Evaluate Trig: g'(0) = 10(0)
- Multiply: g'(0) = 0
Step-by-step explanation:
Hey, there!!
Given that,
{ we can write (a^2-4) as (a^2 - 2^2) also as (x^2- 9) can be written as (x^2 - 3^2)}.
We have a^2-b^2= (a+b) (a-b), so keep same formula on it.
(x+3) in numerator and denominator gets cancelled,
Therefore, (x-3) is the final value.
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>