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2 years ago

Which of the following rational functions is graphed below?

Mathematics

1 answer:

Mekhanik [1.2K]2 years ago

3 0

The graph represents the function (D) because the graph of the function is not defined at x = 1 and x = 2 option (D) is correct.

<h3>What is a function?</h3>

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have a graph of a function:

If we take the function:

$\rm f(x) = \dfrac{1}{\left(x-1\right)\left(x-2\right)}$

At x = 1 and x = 2 the function will be not defined, so this region would be hollow and as we can see in the graph of a function.

The function is not defined at x = 1 and x = 2.

Thus, the graph represents the function (D) because the graph of the function is not defined at x = 1 and x = 2.

Learn more about the function here:

brainly.com/question/5245372

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They increased it by $10.

It ended up costing $60.

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Answer:

$41.0625

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A ship's sonar finds that the angle of depression to a wreck on the bottom of the ocean is 15.20. If a point on

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2 years ago

You go to the pet store and buy a goldfish which sells for $2.00. The store charges 9% sales tax. How much tax will you pay?

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3 0

2 years ago

A tank initially has 300 gallons of a solution that contains 50 lb. of dissolved salt. A brine solution with a concentration of

belka [17]

Let s(t) be the amount of salt in the tank at time t. Then s(0) = 50 lb.

Salt flows into the tank at a rate of

(2 gal/min) (6 lb/gal) = 12 lb/min

and flows out at a rate of

(2 gal/min) (s(t)/300 lb/gal) = s(t)/150 lb/min

so that the net rate at which salt is exchanged through the tank is

ds(t)/dt = 12 - s(t)/150 … (lb/min)

Solve for s(t). The DE is separable, so we have

ds/dt = 12 - s/150

150 ds/dt = 1800 - s

150/(1800 - s) ds = dt

Integrate both sides to get

-150 ln|1800 - s| = t + C

Solve for s :

ln|1800 - s| = -t/150 + C

1800 - s = exp(-t/150 + C )

1800 - s = C exp(-t/150)

s = 1800 - C exp(-t/150)

Now given that s(0) = 50, we solve for C :

50 = 1800 - C exp(-0/150)

50 = 1800 - C

C = 1750

Then the amount of salt in the tank at any time t ≥ 0 is

s(t) = 1800 - 1750 exp(-t/150)

To find the time it takes for the tank to hold 100 lb of salt, solve for t in

100 = 1800 - 1750 exp(-t/150)

1700 = 1750 exp(-t/150)

34/35 = exp(-t/150)

ln(34/35) = -t/150

t = -150 ln(34/35) ≈ 4.348

So it would take approximately 4.348 minutes.

By the way, we didn't have to solve for s(t), we could have instead stopped with

-150 ln|1800 - s| = t + C

Solve for C - this C is not the same as the one we found using the other method. s(0) = 50, so

-150 ln|1800 - 50| = 0 + C

C = -150 ln|1750|

==> t = 150 ln(1750) - 150 ln|1800 - s|

Then s(t) = 100 lb when

t = 150 ln(1750) - 150 ln(1700)

t = 150 ln(1750/1700)

t = 150 ln(35/34)

t ≈ 4.348

5 0

3 years ago

Which of the following rational functions is graphed below?​

Which of the following rational functions is graphed below?