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3 years ago

Graph the image of this figure after a dilation with a scale factor of 2 centered at the origin.

Mathematics

1 answer:

KonstantinChe [14]3 years ago

7 0

The coordinates for this would be : (2, -2)
(6, -2) (6, 4) and (2, 4)

I hope that this helps you !

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Show me how to make 33 in four different ways

tamaranim1 [39]

30+3
11*3
10*3+3
60-30+3

(sorry if these didn't help i'm a beginner and i'm in 7th grade)

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3 years ago

Does the equation have a max or min

Yakvenalex [24]

Answer:

Min

Step-by-step explanation:

To check if it has a max or min, you must reference the a value. The a value in this case is 2, and that is positive. Positive parabolas point up, so they can only have a minimum point.

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3 years ago

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butalik [34]

Answer:

Vertical stretch of factor of 3

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Step-by-step explanation:

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3 years ago

Please help me Algebra 1

Oduvanchick [21]

Answer:

a. $\sqrt{x^n}$ = $x^\frac{n}{2}$

b. $\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

Step-by-step explanation:

a) When n is even, then it is divisible by 2. Because of this, you can write:

$\sqrt{x^n} = (x^n)^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{n}{2}$

b) When n is odd, then n - 1 is even. This would make it divisible by 2, and there would be a remainder of 1, so we can write:

$\sqrt{x^n} = (x^n^-^1^+^1) ^\frac{1}{2}$

$\sqrt{x^n} = (x^n^-^1$ × $x)^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{(n-1)}{2}$ × $x^\frac{1}{2}$

$\sqrt{x^n} = x^\frac{(n-1)}{2}\sqrt{x}$

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2 years ago

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The number name of 70080067 In Indian System

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Answer:

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Step-by-step explanation:

70080067

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2 years ago