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3 years ago

DOES SOMEONE KNOW HOW TO DO THIS

Mathematics

1 answer:

34kurt3 years ago

4 0

Answer:

yah how do u do that

Step-by-step explanation:

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What is negative 8 times negative 8

Vlad1618 [11]

-64 use a calculator

3 0

3 years ago

Read 2 more answers

What polynomial must be added to 3x2 + 4x + 7 to obtain the sum of 0?

Dovator [93]

Answer:

do (3x2+4x+7)+y=0

y=-3x^2-4x-7

5 0

2 years ago

heyyy i did question A but im stuck on question b so if you could help i would really appreciate it it is an emergency <3

stellarik [79]

Answer:

86 cm²

Step-by-step explanation:

Ok, so since 4 circles fit in the square, each circle's diameter must be 10.

Which means the radius of each circle is 5 because 10 ÷ 2 = 5.

Now we can solve for area.

A = πr²

A = 3.14 x 5²

A = 3.14 x 25

A = 78.5 cm²

78.5 cm² is the area of one circle so we multiply that by 4.

78.5 x 4 = 314 cm²

Now we subtract from the area of the square.

20 x 20 = 400 cm²

400 - 314 = 86 cm²

8 0

2 years ago

The one-to-one functions g and h are defined as follows

Debora [2.8K]

Answer:

$g^-^1(x)=-8$

$h^-^1(x)=\frac{x-4}{3}$

$(h^-^1 \ o\ h)(-3)=-3$

Step-by-step explanation:

When given the following functions,

$g=[(-2,-7),(4,6),(6,-8),(7,4)]$

$h(x)=3x+4$

One is asked to find the following,

1. Question 1

$g^-^1(4)$

When finding the inverse of a function that is composed of defined points, one substitutes the input given into the function, then finds the output. After doing so, one must substitute the output into the function, and find its output. Thus, finding the inverse of the given input;

$g^-^1(4)$

$g(4)=6\\g(6)=-8\\g^-^1(4)=-8$

2. Question 2

$h^-^1(x)$

Finding the inverse of a continuous function is essentially finding the opposite of the function. An easy trick to do so is to treat the evaluator (h(x)) like another variable. Solve the equation for (x) in terms of (h(x)). Then rewrite the equation in inverse function notation,

$h(x)=3x+4\\\\h(x)-4=3x\\\\\frac{h(x)-4}{3}=x\\\\\frac{x-4}{3}=h^-^1(x)$

$h^-^1(x)=\frac{x-4}{3}$

3. Question 3

$(h^-^1 \ o\ h)(-3)$

This question essentially asks one to find the composition of the function. In essence, substitute function (h) into function ( $h^-^1$ ) and simplify. Then substitute (-3) into the result.