The value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
<h3>What is the value of sin (π/2)?</h3>
The value of sin (π/2) is equal to the number 1. The value of the sin-1(1) has to be find out.
Suppose the value of this function is <em>x</em>. Thus,
Solve it further,
......1
The value of sin (π/2) and -sin (-π/2) is equal to 1 such that,
Put this value in the equation 1,
Thus, the range will be,
Thus, the value of sin-1(1) is negative startfraction pi over 2 endfraction, startfraction -pi over 2 endfraction.
Learn more about the sine values here;
brainly.com/question/10711389
Answer: Use the function f(x)=x2-2x+8 and the graph of g(x) to determine the difference betw een the maximum value of g(x) and the minimum value of f(x).
Answer:
s = 6
Step-by-step explanation:
8(s+3) = 72
Expand the brackets out:
(8 x s) + (8 x 3) = 72
8s + 24 = 72
Now you get rid of 24 on the left, by taking away 24. But you also have to do the same on the right side so that both sides are equal:
8s + 24 = 72
left(-24) = right (-24)
So that leaves you with:
8s = 48
Now divide both sides by 8 to make them equal and to get s on its own:
8s = 72
left(/8) = right (/8)
Therfore:
s = 6
Answer:
On Paper
Step-by-step explanation:
On the Paper
I hope this helped!
<u>Answer:</u>
The correct answer options are C. 
and D. 
.
<u>Step-by-step explanation:</u>
The values which make the denominator equal to zero are called the excluded values.
Here, we can substitute 8 for x and check if it makes the denominator 0.
