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2 years ago

Help me its due it a little bit

Mathematics

1 answer:

andrezito [222]2 years ago

4 0

Answer:

its b 0.6

Step-by-step explanation:

the reason i see that, is because the points that meet on the tax are going by 0.6

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in an experiment, the temperature dropped 2 degrees each day until the temperature reaches negative 5.5 degrees. if the starting

WITCHER [35]

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around 19 days

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3 years ago

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Bad White [126]

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2 years ago

I need help answering this question. Any ideas on what it could be?

Lesechka [4]

Is this for a test/exam?

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2 years ago

Please help I can’t figure it out

Lynna [10]

Answer:

149.71

Step-by-step explanation:

6 0

2 years ago

Read 2 more answers

I need answer Immediately pls!!!!!!

Illusion [34]

Given:

Total number of students = 27

Students who play basketball = 7

Student who play baseball = 18

Students who play neither sports = 7

To find:

The probability the student chosen at randomly from the class plays both basketball and base ball.

Solution:

Let the following events,

A : Student plays basketball

B : Student plays baseball

U : Union set or all students.

Then according to given information,

$n(U)=27$

$n(A)=7$

$n(B)=18$

$n(A'\cap B')=7$

We know that,

$n(A\cup B)=n(U)-n(A'\cap B')$

$n(A\cup B)=27-7$

$n(A\cup B)=20$

Now,

$n(A\cup B)=n(A)+n(B)-n(A\cap B)$

$20=7+18-n(A\cap B)$

$n(A\cap B)=7+18-20$

$n(A\cap B)=25-20$

$n(A\cap B)=5$

It means, the number of students who play both sports is 5.

The probability the student chosen at randomly from the class plays both basketball and base ball is

$\text{Probability}=\dfrac{\text{Number of students who play both sports}}{\text{Total number of students}}$

$\text{Probability}=\dfrac{5}{27}$

Therefore, the required probability is $\dfrac{5}{27}$ .

3 0

2 years ago