Answer:
Thank you
Step-by-step explanation:
:)
Answer:
= 2x^4 + 6x^3 - 8x^2 + 24x
= 2x ( 2x^3 + 3x^2 - 4x + 12)
Step-by-step explanation:
(X^2 + x - 6) (2x^2 + 4x) =
Let's open the brackets carefully
x^2 * 2x^2 + x^2*4x + x*2x^2 + x*4x - 6*2x^2 - 24x
= 2x^4 + 4x^3 + 2x^3 + 4x^2 - 12x + 24x
= 2x^4 + 6x^3 - 8x^2 + 24x
= 2x ( 2x^3 + 3x^2 - 4x + 12)
Answer is <span>A.
associative property
...................regrouped</span>
B because 6 times 2 is 12...
I believe you need to solve this using the quadratic formula!
To begin, this is what it is:
x= -b ± <span>√ b^2 - 4ac / 2a
Just plug in what you have in your problem...
2 being a, 13 being b, and -24 being c.
So we get:
x= -13 </span>± <span>√13^2 - 4(2)(-24) / 2(2)
x= -13 </span><span>± √169 - 8 (-24) / 4</span>
<span>x= -13 <span>± √169 + 192 / 4</span>
x= -13 </span>± √<span>361 / 4
The square root of 361 is 19.
So you have: -13 </span><span>± 19 / 4.
Here's where you take the equation </span>-13 <span>± 19 and put the addition and subtraction sign to use.
-13 - 19 = -32
and
-13 + 19 = 6
Now all is left to do is divide the two numbers by 4.
-32/4 = -8
and
6/4 = 3/2
x = -8, 3/2</span>
