Question

For this item, any non integer answer should be entered as a decimal rounded to the hundredths place. Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots. if the player shoots twice, the probability that he scores a goal both times is what percent ?

Answer 1

Answer:

probability that he scores a goal both times is $13.7%$.

Step-by-step explanation:

It is given that Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.

Therefore, P(X)=0.63.

Thus, the probability of getting success in his shoots will be,

$P(X^{c})=1-P(X)=1-0.63=0.37$

probability that he scores a goal both times is =$P(X^c){\times}P(X^c)$

=$0.37{\times}0.37$

=$0.137$

=13.7%