We know, acceleration = change in velocity / Time
a = 20 - 0 / 3.5
a = 20 / 3.5
a = 5.7 m/s2
In short, Your Answer would be Option B
Hope this helps!
Answer:
We are heating the sample repeatedly to become a pure compound of only MgSO4 (withot H2O) and a constant mass.
Explanation:
Step 1: Data given
Mass of MgSO4·7H2O = 5.06 grams
The remaining MgSO4 had a constant mass of 2.47 grams.
Step 2: Explain why the sample in the crucible was heated repeatedly until the sample had a constant mass.
Before heating the compound has magnesium sulfate and water.
The total mass of this compound is 5.06 grams
By heating we try to eliminate the water.
After heating there remain mgSO4 with a mass of 2.47 grams
This means 5.06 - 2.47 = 2.59 grams is water. All of this is eliminated.
The heating process happens repeatedly to make sure the final compound is pure. So the 2.47 grams os only MgSO4. If the mass would not be constant. It means the compound is not pure, the not all the water is eliminated yet.
So we are heating the sample repeatedly to become a pure compound of only MgSO4 (withot H2O) and a constant mass.
Answer:
2Cu + O2 ----------------> 2CuO
Answer:
(δ+) C → O (δ-)
(δ-) O ← Cl (δ+)
(δ+) O → F (δ-)
(δ+) C → N (δ-)
(δ-) Cl ← C (δ+)
(δ-) S ← H (δ+)
(δ+) S → Cl (δ-)
Explanation:
The polarity of a bond depends on the difference of electronegativity (EN) between the atoms that form it. The dipole moment (μ) points to the atom with the highest electronegativity, which is the one with a negative charge density (δ-), while the other atom has a positive charge density (δ+).
<em>The first bond is between C and O. </em>
EN(C) = 2.5; EN (O) = 3.5
(δ+) C → O (δ-)
<em>The second bond is between O and Cl. </em>
EN(O) = 3.5 ; EN(Cl) = 3.0
(δ-) O ← Cl (δ+)
<em>The third bond is between O and F. </em>
EN(O) = 3.5; EN(F) = 4.0
(δ+) O → F (δ-)
<em>The fourth bond is between C and N. </em>
EN(C) = 2.5; EN(N) = 3.0
(δ+) C → N (δ-)
<em>The fifth bond is between Cl and C. </em>
EN(Cl) = 3.0; EN(C) = 2.5
(δ-) Cl ← C (δ+)
<em>The sixth bond is between S and H. </em>
EN(S) = 2.5; EN(H) = 2.1
(δ-) S ← H (δ+)
<em>The seventh bond is between S and Cl.</em>
EN(S) = 2.5; EN(Cl) = 3.0
(δ+) S → Cl (δ-)
Over the ocean, the temperature rises much slower, because the water evaporates causing the hot molecules to go into the atmosphere, and the overall temperature of the water doesn't increase much, this causes the area without the water to be much hotter.