Here's my best guess
the volume of the unit cell is (385*10^-12)^3=5.7066*10^-29 m^3
multiply by density to get mass
mass = (7 g/cm^3)*(100^3 cm^3 / 1^3 m^3) * 5.7066*10^-29 m^3= 3.99466*10^-22 g
covert to moles
3.99466*10^-22 g * 1 mol / 239.82 g = 1.6657 *10^-24 mol
convert to number of units
1.6657 *10^-24 mol * 6.23*10^23 units/mol = 1.04
385 pm = 3.85*10^(-8) cm
The volume of the unit cell is the cube of that, which is 5.71*10^(-23) cm^3. Since the ratio of mass to volume (i.e. the density) must be the same no matter what amount of TlCl you have, you can say:
7 = x/(5.71*10^(-23)), where x is the mass of the unit cell. Solving for x, you get 4*10^(-22) g.
The mass of a molecule of TlCl is 240 amu, which in grams is 4*10^(-22) g. The mass of the unit cell and the mass of a molecule of TlCl is the same. Therefore there is one formula unit of TlCl per unit cell.
When 67 g of water is heated from its melting point to its boiling point, it takes 28006 J of heat.
<h2>Relationship between heat production and temperature change</h2>
- A way to numerically relate the quantity of thermal energy acquired (or lost) by a sample of any substance to that sample's mass and the temperature change that results from that is provided by specific heat capacity.
The following formula is frequently used to describe the connection between these four values.
q = msΔT
where, q = the amount of heat emitted or absorbed by the thing
m = the object's mass = 67 gm
s = a specific heat capacity of the substance = 4.18 J/gC
ΔT = the resultant change in the object's temperature = 373.15 -273.15K= 100 k
q = 67 * 4.18 * 100 J
⇒q = 28006 J
Therefore it is concluded that 67 g of water takes 28006 J of heat from its melting point to reach its boiling point.
Learn more about thermal energy here:
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Because distances Between large objects in space are not VERY convenient
Answer:
Explanation:
Ideal gases follow the combined law of gases:
Where,
- Pressure is the absolute pressure and its units may be in any system, as long as they are the same for both states.
- Also, volume may be in any units, as long as it they are the same for both states.
- Temperature must be absolute temperature, whose unit is Kelvin.
Your data are:
- P₁ = 1200.00 mmHg
- P₂ = 1.11842 atm
- V₁ = 85.0 mL
- V₂ = 350.0 mL
- T₂ = ?
- T₁ = 90.0ºC
<u>1. Conversion of units:</u>
- P₁ = 1200.00 mmHg × 1.00000 atm / 760.000 = 1.578947 mmHg
- T₁ = 90.00ºC + 273.15 = 363.15K
<u>2. Solution</u>
- Clearing T₂, from the combined gas equation you get:
