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3 years ago

Help plz! im not understanding

Chemistry

1 answer:

valina [46]3 years ago

4 0

a is 8.46 × 10^5

b is 3 ×10^-2

Explanation:

i hope this helps

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What is the density of a substance with a mass of 0.0450 and a volume of 26.4?

Tanya [424]

Answer:

$density \: = \frac{mass}{volume} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = \frac{0.0450}{26.4} \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: = 0.0017 \\$

Explanation:

plz....

Mark it as a brilliant answer

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4 years ago

Read 2 more answers

You have an evacuated container of fixed volume and known mass and introduce a known mass of a gas sample. measuring the pressur

balandron [24]

Answer is: <span>the gas undergoes a chemical reaction that has fewer gas particles in products than in reactants. pressure is directly proportional to number of particles, so the pressure decreased.
Ideal gas law: PV = nRT. If amount of substance decreased, pressure also decreased.</span>

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4 years ago

How much energy is evolved during the reaction of 51.2 g of al, according to the reaction below? assume that there is excess fe2

sesenic [268]

Answer : The amount of energy evolved during the reaction is, $-807.696KJ$ .

Solution : Given,

$\Delta H=-852KJ$

Mass of Al = 51.2 g

Molar mass of Al = 27 g/mole

First we have to calculate the moles of Al.

$\text{ Moles of Al}=\frac{\text{ Mass of Al}}{\text{ Molar mass of Al}}=\frac{51.2g}{27g/mole}=1.896moles$

The balanced combustion reaction is,

$Fe_2O_3+2Al\rightarrow Al_2O_3+2Fe$

From the given reaction, we conclude that

As, 2 moles of Al evolved energy = $-852KJ$

So, 1.896 moles of Al evolved energy = $\frac{-852KJ}{2moles}\times 1.896moles=-807.696KJ$

Therefore, the amount of energy evolved during the reaction is, $-807.696KJ$ .

8 0

3 years ago

Plastic disintegrates faster in land or water

anzhelika [568]

answer: WATER

hopes that helps

5 0

3 years ago

What volume of solution would be present if 40.0 g Caci, would be used to make a 0.600M

True [87]

Answer:

$\large \boxed{\text{601 mL}}$

Explanation:

1. Calculate the moles of CaCl₂.

$\text{Moles} = \text{40.0 g} \times \dfrac{\text{1 mol}}{\text{110.98 g}} = \text{0.3604 mol}$

Step 2. Calculate the volume of CaCl₂ solution

$\begin{array}{rcl} n &= &\dfrac{c}{V}\\\\\dfrac{\text{0.600 mol}}{\text{1 L}} &=& \dfrac{\text{0.3604 mol}}{V}\\\\ \dfrac{0.600V}{\text{1 L}} & = & 0.3604\\\\0.600V &= & \text{0.3604 L}\\V & = & \dfrac{\text{0.3604 L}}{\text{0.600 L}}\\\\ & = & \text{0.601 L}\\& = & \textbf{601 mL}\\\end{array}\\\text{The volume of the solution would be $\large \boxed{\textbf{601 mL}}$}$

8 0

3 years ago