It's not specified whether 1 is the 1st or 2nd roll: HOWER:
The 1st Roll is "1": P(odd sum/the 1st Roll is 1)
What is the sample space of all numbers starting with "1":
{(1,1), (1,2), (1,3), (1,4), (1,5), (1,6),} = 6
the couple of add sum=(1,2), (1,4), (1,6), =3
P(odd sum/ 1st is 1) = 3/6 =1/2
or in applying the formula:
P(odd sum/the 1st Roll is 1) =P(odd sum ∩ 1) / P(getting "1") it will give the same probability = 1/2
NOW if the 2nd Roll is "1", it 's still 1/2
Answer:
8.75cm²
Step-by-step explanation:
First we need to find the angle subtended by the arc
L = theta/360 * 2pir
3.5 = theta/360 * 2*3.14(5)
3.5 = theta/360 * 31.4
theta/360 = 3.5/31.4
theta/360 = 0.11146
theta = 0.11146 * 360
theta = 40.13 degrees
Area of the sector = theta/360 * pir^2
Area of the sector = 40.13/360 * 3.14*25
Area of the sector = 40.13/360 * 78.5
Area of the sector = 8.75cm
Hence the area of the sector is 8.75cm²
Answer:
Bus B travel faster
Step-by-step explanation:
The graph of the question in the attached figure
we know that
the linear equation in slope intercept form is equal to
where
m is the slope
b is the y-intercept
x ---> is the time in hours
y ---> is the distance in miles
In this problem we have
Bus A
The slope of the linear equation represent the speed of the bus
so
The speed of bus A is
Bus B
Find the slope
take two points from the graph
(0,0) and (3,200)
The formula to calculate the slope between two points is equal to
substitute
Compare the slope Bus A with the slope Bus B
therefore
Bus B travel faster
8x+30/10
Simplify the Problem
<em><u>8x+3</u></em>
