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castortr0y [4]
2 years ago
9

Point G is rotated 90°. The coordinate of the pre-image point G was (7, –5), and its image G’ is at the coordinate (5, 7). What

is the direction of the rotation?
A. counter-clockwise
B. horizontally
C. symmetrical
D. clockwise
Mathematics
1 answer:
zlopas [31]2 years ago
5 0

Answer:

D.Clockwise

Step-by-step explanation:

90 Degree Rotation

When rotating a point 90 degrees counterclockwise about the origin our point A(x,y) becomes A'(-y,x). In other words, switch x and y and make y negative.

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Main content

Rotations

Rotating shapes about the origin by multiples of 90°

Learn how to draw the image of a given shape under a given rotation about the origin by any multiple of 90°.

Introduction

In this article we will practice the art of rotating shapes. Mathematically speaking, we will learn how to draw the image of a given shape under a given rotation.

This article focuses on rotations by multiples of 90^\circ90∘90, degrees, both positive (counterclockwise) and negative (clockwise).

Part 1: Rotating points by 90^\circ90∘90, degrees, 180^\circ180∘180, degrees, and -90^\circ−90∘minus, 90, degrees

Let's study an example problem

We want to find the image A'A′A, prime of the point A(3,4)A(3,4)A, left parenthesis, 3, comma, 4, right parenthesis under a rotation by 90^\circ90∘90, degrees about the origin.

Let's start by visualizing the problem. Positive rotations are counterclockwise, so our rotation will look something like this:

yyxxA'A′\blueD{A(3,4)}A(3,4)

Cool, we estimated A'A′A, prime visually. But now we need to find exact coordinates. There are two ways to do this.

Solution method 1: The visual approach

We can imagine a rectangle that has one vertex at the origin and the opposite vertex at AAA.

\small{1}1\small{2}2\small{3}3\small{4}4\small{5}5\small{6}6\small{7}7\small{8}8\small{9}9\small{\llap{-}2}-2\small{\llap{-}3}-3\small{\llap{-}4}

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Answer:

d_{AB}\ne d_{JK}

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Option (A) is false

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Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

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Finding the length of AB using the formula

d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

        =\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}

         =\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}

         =\sqrt{6^2+1}

         =\sqrt{36+1}

        =\sqrt{37}

d_{AB}\:=\sqrt{37}

d_{AB}=6.08 units        

Given the vertices of the segment JK

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From the graph, it is clear that the length of JK = 5 units

so

d_{JK}=5 units

Given the vertices of the segment GH

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  • H(-2, -2)

Finding the length of GH using the formula

d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}

         =\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}

          =\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}

          =\sqrt{3^2+0}

           =\sqrt{3^2}

\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0

d_{GH}\:=\:3 units

Thus, from the calculations, it is clear that:

d_{AB}=6.08  

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d_{GH}\:=\:3

Thus,

d_{AB}\ne d_{JK}

d_{AB}\ne \:d_{GH}

d_{GH}\ne \:d_{JK}

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

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